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frutty [35]

$\dfrac{\sec^2x}{\sec^2x-1}=\dfrac{\sec^2x}{\tan^2x}=\dfrac{\frac1{\cos^2x}}{\frac{\sin^2x}{\cos^2x}}=\dfrac1{\sin^2x}=\csc^2x$

5 0

3 years ago

Neporo4naja [7]

I hope this helps you

3 0

3 years ago

Mnenie [13.5K]

Answer:

2267.97 grams

Step-by-step explanation:

i hope this helps!

6 0

3 years ago

defon

Answer:

x=16 1/4

Step-by-step explanation:

is that a 11/2 or a 1 1/2? the answer i put was for 1 1/2

8 0

3 years ago

nasty-shy [4]

Answer: B. False
Distance between points is square root of (x1 - x2) + (y1 - y2).

Hope it helped!

8 0

3 years ago