Question

The distance an object is from the ground after being tossed from a hot air balloon 850 feet in the air is a function of​ time: ​f(t)=-16.1t^2 +5.8t+850, where​ f(t) is height and t is the amount of time the object has been in the air. Predict the height of the object after 5.5 seconds.

Answer 1

The height of the object after 5.5 seconds is 394.875feet

Functions and values

Given the function that represents the height of the ball as shown:

$f(t)=-16.1t^2 +5.8t+850$

In order to determine the  height of the object after 5.5 seconds, we will substitute t = 5.5s into the formula to have;

$f(5.5)=-16.1(5.5)^2 +5.8(5.5)+850\\f(5,5)=-487.025+31.9+850\\f(5.5)=394.875feet$

Hence the height of the object after 5.5 seconds is 394.875feet

Learn more on functions here: brainly.com/question/10439235

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