Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
I. kinda confused I may be reading it wrong but 3
Answer: 2
Step-by-step explanation:
First you have to plug in the value for x which is -18 so then you're equation then get y by itself and solve for y. This becomes
-3(-18) -y = 56
54 - y = 56
-54 -54
Y=2
You can check your work by plugging in 18 for x and 2 for y and when you solve the equation your answer should equal 56.
Answer:
3$
Step-by-step explanation: if he try to buy as many balloons as passible with the money he has it would be 3$
Answer:
yo emanuael
Step-by-step explanation:
