Unfortunately, I don’t knooow :(
Answer:
b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)
Step-by-step explanation:
A. <em>Solve for b₁
</em>
a = ½(b₁ + b₂)h Multiply each side by 2
2a = (b₁ + b₂)h Remove parentheses
2a = b₁h + b₂h Subtract b₂h from each side
2a - b₂h = b₁h Divide each side by h
b₁ = (2a – b₂h)/h Remove parentheses
b₁ = (2a)/h – b₂
B. <em>Solve for h
</em>
2a = (b₁ + b₂)h Divide each side by (b₁ + b₂)
h = (2a)/(b₁ + b₂)
<em>Note: I am assuming your second equation is:</em>
<em>x = 2y - 1</em>
<em></em>
Answer:
The solution to the system of equations is:
Step-by-step explanation:
Given the system of equations
2x+y=3
x = 2y - 1
solving the system of equations using the elimination method

Arrange equation variables for elimination

Multiply x-2y=-1 by2: 2x-4y=-2

subtracting the equations




now solve -5y = -5 for y

Divide both sides by -5

Simplify

For 2x+y=3 plug in y=1

subtract 1 from both sides

Simplify

Divide both sides by 2

Simplify

Therefore, the solution to the system of equations is:
The answer is the second one.
The one that shows 5 square root of 2.