2 years ago

PLEASE HELP ME PLEASE!!

Mathematics

1 answer:

Anna35 [415]2 years ago

8 0

Step-by-step explanation:

in such a case, where we have all the sides and need angles, the best tool is the extended Pythagoras (for general triangles and not just for right-angled ones) :

c² = a² + b² - 2ab×cos(C)

c is the side opposite of angle C.

the side opposite of B is CA.

so, we have

220² = 100² + 160² - 2×100×160×cos(B)

48,400 = 10,000 + 25,600 - 32,000×cos(B)

12,800 = -32,000×cos(B)

cos(B) = -12,800/32,000 = -0.4

B = 113.5781785...° ≈ 114°

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3 years ago

6. a. Name a pair of equations that have exactly one point of intersection. How do you know?

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Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe

And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it