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kotykmax [81]
3 years ago
9

Elimination 4x+5y=-15 -3x-2y=13

Mathematics
1 answer:
AveGali [126]3 years ago
4 0
Multiply the first equation by 3 and tge second by 4:
12x+15y=-45
-12x-8y=52
then add the equations:
0x+7y=7
7y=7
y=1
so 4x+5(1)=-15
4x+5=-15
4x=-20
x=-5
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If 3y+2 is an odd integer then what is the odd integer that follows it
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3y + 4

Step-by-step explanation:

All odd integers are 2 units appart.Take for example the odd integers: 1, 3, 5, 7, 9, they all are 2 units apart from the next odd integer. Therefore, if 3y + 2 is an odd integer, then the next odd integer is 3y + 2 + 2 = 3y + 4. For example, if y = 1 , then the first odd integer is 3(1) + 2 = 5, and the odd integer that follows it is 3(1) + 4 = 7

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Consider the two functions. F(x)=x^2-8x+7
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(X-7)(x-1)

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3 years ago
PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

4 0
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Answer: 27.00

Step-by-step explanation:

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