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Lorico [155]
3 years ago
14

6 to the 2nd power ÷ 2(3) + 4

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0
6 to the second power means 6²

So,

6² ÷ 2 ( 3 ) + 4
 
=36/2(3)+4

=(18)(3)+4

=54+4

=58


lesantik [10]3 years ago
8 0
For this case we have the following expression:
 "6 to the 2nd power ÷ 2(3) + 4"
 Rewriting the expression in algebraic form we have:
 \frac{6^2}{2(3)+4}
 Rewriting the numerator we have:
 \frac{36}{2(3)+4}
 Rewriting the denominator we have:
 \frac{36}{6+4}
 \frac{36}{10}
 \frac{18}{5}
 Dividing both numbers we have:
 \frac{18}{5} = 3.6
 Answer:
 
The result of the given expression is: 
 
\frac{6^2}{2(3)+4}=3.6

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tester [92]

Answer: 59

Step-by-step explanation:

4 0
2 years ago
2) f(x) = x² **<br> g(x)= 3x – 2<br> Find f(g(-4)
Usimov [2.4K]

Answer:

f(g( - 4)) = 196

Step-by-step explanation:

The functions are;

f(x) =  {x}^{2}

and

g(x) = 3x - 2

We want to find

f(g( - 4))

First we find g(-4) to get:

g( - 4) = 3 \times  - 4 - 2

g( - 4) =  - 12- 2

g( - 4) =  - 14

Now

f(g( - 4)) = f( - 14)

This implies that,

f(g( - 4)) = {( - 14)}^{2}

f(g( - 4)) = {( - 14)} \times  - 14

f(g( - 4)) = 196

6 0
3 years ago
A group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students
ValentinkaMS [17]

Answer:

A maximum of 43 students and 11 teachers can go to the trip.

Step-by-step explanation:

Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:

4 + 1 = 5

54/5 = X

10.8 = X

10 x 4 = 40

10 x 1 = 10

4 - 1 = 3

Therefore, a maximum of 43 students and 11 teachers can go to the trip.

8 0
3 years ago
What is 5(34)68+76 can u guys give me the answer I really need help
Ratling [72]
5x34= 170
68+76= 144
170+144= 314
4 0
4 years ago
Read 2 more answers
Help please <br><br> marking brainlist
luda_lava [24]
I can help you but i cant see with the reflection thingy
4 0
3 years ago
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