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Lorico [155]
3 years ago
14

6 to the 2nd power ÷ 2(3) + 4

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0
6 to the second power means 6²

So,

6² ÷ 2 ( 3 ) + 4
 
=36/2(3)+4

=(18)(3)+4

=54+4

=58


lesantik [10]3 years ago
8 0
For this case we have the following expression:
 "6 to the 2nd power ÷ 2(3) + 4"
 Rewriting the expression in algebraic form we have:
 \frac{6^2}{2(3)+4}
 Rewriting the numerator we have:
 \frac{36}{2(3)+4}
 Rewriting the denominator we have:
 \frac{36}{6+4}
 \frac{36}{10}
 \frac{18}{5}
 Dividing both numbers we have:
 \frac{18}{5} = 3.6
 Answer:
 
The result of the given expression is: 
 
\frac{6^2}{2(3)+4}=3.6

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In the figure, TP and TS are opposite rays. TQ bisects &lt; RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

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6 0
2 years ago
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