For this case we have the following expression: "6 to the 2nd power ÷ 2(3) + 4" Rewriting the expression in algebraic form we have: Rewriting the numerator we have: Rewriting the denominator we have: Dividing both numbers we have: Answer: The result of the given expression is:
The maximum is 5, and the minimum is 1. The max. is in the are on the same side, which combines forces of 3 and 2. The min. uccors when they are on opposite sides.