Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
(X+60)(x+2) is the answer
No no. no no n on o n in o n o b o n
Answer:
132
Step-by-step explanation:
Find Radius (r)
42/2 = 21
Plug 21 into Circumference Equation
2πr (In this case, π is 22/7)
Simplify
42 (22/7)
<u>132</u>
Tim spends 1/3 each weekday sleeping and 7/24 in school. We can write 1/3 as 8/24 so we have a common denominator. Now we can see that Tim sleeps for 1/24 time of a weekday more then he spends in school.
I hope that's what you meant.
