There are two solutions to this question, one is positive and the other is negative:
Answer:
x = 2
Step-by-step explanation:
2(2x+1-x)=6
2(x+1)=6 add common factors
2x+2=6 distribute the 2
2x=4 subrtract 2 on both sides
x=2 divide 2 on both sides
Solution:
<u>We know that:</u>
<em>Since we are already given the base and the height, we can substitute them into the formula to find the area of the triangle.</em>
<u>Cancel out the "2" by dividing it by 18.</u>
<u>Simplify the multiplication.</u>
Thank you very much and this “question” was very helpful for me.
You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:
Note that if <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).
Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,
b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.
Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then
(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,
- b plus sqrt( b^2 - 20a )
d = ------------------------------------
2a
and
</span> - b minus sqrt( b^2 - 20a )
e = ------------------------------------
2a
Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?
