Since the numbers are consecutive, they must be near each other in size, and therefore near one-third of 168. And since the lower number is -2 off the middle, and the upper number is +2 from the middle, the middle number must be exactly one-third of 168—otherwise the sum of the three could never be 168. Labelling the three consecutive numbers as x, y, and z:
x + y + z = 168
(y-2) + y + (y+2) = 168.
3y = 168
y = 56
therefore the smallest number (x) = 54.
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Related Questions (More Answers Below)
z and 100 are on the same line so the total is 180
180-100=z
80=z
Please give Brianest
First find the equation of the line:
y - b = m (X - a)
y - 5 = 2/3 (X + 2)
3y - 15 = 2 (X + 2)
3y - 15 = 2x + 4
3y = 2x + 19
Then sub the y-value of A into the equation to find X.
y = 3
3(3) = 2x + 19
9 = 2x + 19
2x = 10
X = 5
And sub the X-value of B into the equation to find y.
X = -2
3y = 2(-2) + 19
3y = -4 + 19
3y = 15
y = 5
B1 = 2
b2 = (b1)^2 + 1 = 2^2 + 1 = 5
b3 = (b2)^2 + 1 = 5^2 + 1 = 26
b4 = (b3)^2 + 1 = 26^2 + 1 = 676+1=<span>677</span>