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lys-0071 [83]
2 years ago
12

Mm E 9. Solve: 3(x+4) ≤36 x> 8 x≤8 x≤12 X>12

Mathematics
2 answers:
grigory [225]2 years ago
5 0

Answer:   x ≤12

Step-by-step explanation:

3(x+4) ≤36

 3x+4 ≤36 (you should simplify)

     3x ≤36 (36 divided by 3 is 12)

       x ≤12

vampirchik [111]2 years ago
4 0

Step-by-step explanation:

3(x+4) ≤ 36

3x + 12 ≤ 36

3x ≤ 24

x ≤ 8

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3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

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z = x + iy

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The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

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|z|\:=\sqrt{6^2+\left(-2\right)^2}

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3 years ago
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Step-by-step explanation:

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3 years ago
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