Answer:
Option (4)
Step-by-step explanation:
Given inequality is,



x ≥ 0 [For x = 0, fraction is not defined]
(x - 6)(x + 6) ≤ 0
x - 6 ≤ 0
x ≤ 6
Or
x + 6 ≤ 0
x ≤ -6
Therefore, solution set is (-∞, -6] ∪ (0, 6]
By plotting the solution area on a number line,
Option (4) will be the answer.
Answer:
C is correct
Step-by-step explanation:
Firstly, we have to solve for x in the solution set of the inequality
We have this as follows;
x + 2 ≥ 6
x ≥ 6-2
x ≥ 4
To graph this, we consider the middle sign which is greater than or equal to
So, the inequality sign has to face the right side
secondly, it has to be shaded on the point 4 due to the fact that it has the ‘equal to’ beneath the single inequality symbol
so, the correct answer here is option C
Answer:
Step-by-step explanation:

The value of 7 in 26..74 is 0.7
The value of 7 in 37.596 is 7.
1/10 the value of 7 in 26.74 is 0.07 and 0.07 ≠ 7.
So, statement a) is incorrect.
1/100 the value of 7 in 26.74 is 0.007 and 0.007 ≠ 7.
So, statement c) is incorrect.
100 times the value of 7 in 26.74 is 70 and 70 ≠ 7.
So, statement d) is incorrect.
10 times the value of 7 in 26.74 is 7 and 7 = 7.
So, statement b) is correct and it correctly compares two values.
Answer:
630
Step-by-step explanation: