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Vika [28.1K]
2 years ago
11

Which 2 numbers have a mean of 10 and a range of 12

Mathematics
1 answer:
mamaluj [8]2 years ago
6 0

Answer:

Step-by-step explanation:

16 - 4 = 12

16 + 4 = 20

then 20 ; 2 = 10

Half of 12 is 6, therefore the two numbers 10 - 6 = 4 and 10 + 6 = 16 will have a mean of 10 and a range of 12.

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If the exterior angle of a regular polygon is 7.2 degrees, what is the name of that polygon?
kirill [66]

A regular polygon with exterior angle of 7.2 degrees is a 50-gon.

<h3>Regular polygon</h3>

Regular polygon are polygon that are equiangular. This simply means they are polygon with equal angles.

The formula to find the number of sides of a polygon using exterior angle is as follows:

  • exterior angle = 360 / n

where

n = number of sides

Therefore,

7.2 = 360 / n

cross multiply

7.2n = 360

divide both sides by 7.2

n = 360 / 7.2

n = 50

The polygon has 50 sides. Therefore, it is a 50-gon

learn more on polygon here: brainly.com/question/12105506

8 0
2 years ago
R varies directly as S and inversely as T. if R = 8 when S = 4 and T = 3, then R is equal to ​
Alex

Answer:

R = 6S/T

Step-by-step explanation:

R ∝ S/ T

》R = kS/ T

》k = RT/ S

If R = 8 when S = 4 and T = 3

then, k = (8 × 3)/ 4

k = 6

∴ R = (6 × S)/ T

5 0
3 years ago
CosA×cos2A+sinA×sin2A=cos (2A-A)​
Aleksandr-060686 [28]

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cos

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7 0
3 years ago
Convert 5 pints to 3 quarts
ludmilkaskok [199]

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6 0
3 years ago
Read 2 more answers
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
3 years ago
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