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QveST [7]
1 year ago
8

Hexagonal chess is played on a regular hexagonal board comprised of 92 small hexagons in three colors. The chess pieces are arra

nged so that a player can move any piece at the start of a game.
a. What is the sum of the measures of the interior angles of the chess board?
Mathematics
1 answer:
Nonamiya [84]1 year ago
8 0

The sum of the measures of the interior angles of the chess board is equal to 720°.

<h3>What is a polygon?</h3>

A polygon can be defined as a two-dimensional geometric shape that comprises straight line segments and a finite number of sides. Also, some examples of a polygon include the following:

  1. Triangle
  2. Quadrilateral
  3. Pentagon
  4. Hexagon
  5. Heptagon
  6. Octagon
  7. Nonagon

<u>Note:</u> The number of sides (n) of a hexagon is 6.

In Geometry, the sum of the interior angles of both a regular and irregular polygon is given by this formula:

Sum of interior angles = 180 × (n - 2)

Sum of interior angles = 180 × (6 - 2)

Sum of interior angles = 180 × 4

Sum of interior angles = 720°.

Read more on sum of interior angles here: brainly.com/question/13293407

#SPJ1

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Kisachek [45]

Answer:

Step-by-step explanation:

A car is rented for $40 per day plus $0.25 per mile driven. The total is $45.50-  40 + 0.25x + 45.50

Karen buys four t-shirts for $45.50. The three red t-shirts each cost 4 times the price of one blue t-shirt.- x + 3(4x) = 45.50

Finn buys a toy boat for $45.50 including tax He was charged 7% sales tax on the original price.- X+0.07% = 45.50

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6 0
3 years ago
Assume that when an adult is randomly​ selected, the probability that they do not require vision correction is 23​%. If 6 adults
KiRa [710]

Answer:

 P(X = 2) = 0.27894

Step-by-step explanation:

Given:

- The probability that no vision correction is required p = 0.23

- No. adults are randomly selected n = 6

Find:

- P ( Exactly 2 dont require vision correction)

Solution:

- We will declare a random variable X is the umber of adults out of 6 that do  not require vision correction. X follows a Binomial distribution:

                                    X~ B ( 6 , 0.23 )

- The probability required is P ( X = 2 )

- Using the pmf of binomial distribution we have:

                           P(X = 2) = 6C2 * (0.23)^2 * (0.77)^4

                           P(X = 2) = 15 * 0.0529 * 0.35153041

                           P(X = 2) = 0.27894

7 0
3 years ago
For the month of March in a certain​ city, 57​% of the days are cloudy. Also in the month of March in the same​ city, 55​% of th
kirill115 [55]

Answer:

P(F | C) = 0.96

Step-by-step explanation:

Hi!

This is a problem on conditional probability. Lets call:

C = { cloudy day }

F = { foggy day }

Then F ∩ C = { cloudy and foggy day }

You are asked for P(F | C), the probability of a day being foggy given it is cloudy. By definition:

P(F|C)=\frac{P(F\bigcap C)}{P(C)}

And the data you have is:

P(C) = 0.57\\P(F \bigcap C) =0.55

Then: P(F | C) = 0.96

3 0
3 years ago
The function f(x)=603(1.3)^x represents the number of students enrolled at a university x years after it was founded. Each year,
Ede4ka [16]

Answer: 0.3 times

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
7. A cylindrical tank can hold 2279.64 cubic feet of water. The radius of the tank is 11 feet. What is the height of the tank?
aliina [53]

Answer:

r = 8.12

Step-by-step explanation:

The volume for a cylinder is V=πr^2h therefore,

v = 2279.64

h = 11ft

r = ?

2279.64 = πr^2 * 11

\frac{2279.64}{11}= {\pi r^2} \\

207.24 = πr^2

\frac{207.24}{\pi} =r^2\\\\66 = r^2\\\\\sqrt{66} = r\\\\\\8.12 = r

3 0
2 years ago
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