actually it is 5% of 100 is 5
Therefore, 5% of 500 is 5 x 5 = 25g
Answer:
67.824
Explanation: You want to use the combined gas law equation (P1*V1)/(n1*T1)=(P2*V2)/(n2*T2). So first cross out what remains constant, so volume(V) and I assume moles (since it was not mentioned as a change). Then you can solve algebraically for the answer!
Hope this helped!
Answer:
The work is -6,497.54 J
Explanation:
Work is the amount of energy transferred from one system to another by a force when a displacement occurs.
The work exchanged for a gas depends on the transformation it performs to go from the initial state to the final state.
The pressure - volume work done by a system that compresses or expands at constant pressure is given by the expression:
W= -P*ΔV
where
- W is the work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J), which is equivalent to Pa*m³
- P: Pressure. Its unit of measurement in the International System is the pascal (Pa).
- ∆V: Volume variation (∆V = Vfinal - Vinitial). Its unit of measurement in the International System is cubic meter (m³)
In this case:
- Wsystem=?
- P= 5.63 atm=570,459.8 Pa (being 1 atm=101325 Pa)
- ΔV=Vfinal - Vinitial= 15.61 L - 4.22 L= 11.39 L= 0.01139 m³ (being 1 L=0.001 m³)
Replacing:
W= -570,459.8 Pa*0.01139 m³
Solving:
W=-6,497.54 J
<u><em>The work is -6,497.54 J</em></u>
The mass percent of sulfurous acid in the new solution : 38.9%
<h3>Further explanation</h3>
<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>
<em />
solution 1
composition :
solution 2(new solution)
composition :
- Total mass of new solution after water evaporated
- %mass of acid in a new solution
C.) Electrical Signals are not used <span>to locate underground oil reserves
Hope this helps!</span>
