Question

Calculate the number of atoms in 0.316 mol of phosphorus

Answer 1

Answer: 7.608 x 10∧23

Explanation:

Using Avogadro's Number;

1 mole of Phosphorus (P4) molecule contains 6.02 x 10∧23 molecules.

∴ 0.316 mole of Phosphorus (P4) will contain; 0.316 x 6.02 x 10∧23 =

    1.902 x 10∧23 molecules.

1 molecule of Phosphorus (P4) is made up of 4 atoms.

∴ 1.902 x 10∧23 molecules Phosphorus (P4) will contain :

  1.902 x 10∧23  x 4 = 7.608 x 10∧23 atoms

  0.316 mole of phosphorus contains 7.608 x 10∧23 atoms.

Answer 2

Answer: The number of atoms of phosphorus are $1.903\times 10^{23}$

Explanation:

We are given:

Number of moles of phosphorus = 0.316 moles

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms

So, 0.316 moles of phosphorus will be present in $\frac{6.022\times 10^{23}}{1}\times 0.316=1.903\times 10^{23}$ number of atoms

Hence, the number of atoms of phosphorus are $1.903\times 10^{23}$