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Anarel [89]
2 years ago
11

Solve for x…………………….

Mathematics
1 answer:
Furkat [3]2 years ago
4 0

Answer:

x = 15

Step-by-step explanation:

the figure has one pair of parallel sides and is therefore a trapezoid.

the lower base angle is supplementary to the upper base angle on the same side, then

8x + 6 + 54 = 180

8x + 60 = 180 ( subtract 60 from both sides )

8x = 120 ( divide both sides by 8 )

x = 15

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James wants to compete in the international speed texting competition next year where participants compete on text speed and acc
lions [1.4K]

Complete question :

James wants to compete in the international speed texting competition next year where participants compete on text speed and accuracy. James’s current text speed is 2 characters per second. James has found that his texting speed increases at a rate of 1⁄2 a character per second for each month that he practices.

1. a. What is James’s new texting speed if he practices for only 1 month? __________

b. What is James’s new texting speed if he practices for 2 months? ____________

c. What is his new texting speed if he practices for 3 months? _____________

d. Write an algebraic equation that gives James’s texting speed s for m months of

practice.

Answer:

2 1/2 ; 3, 3 1/2 ; s = 2 + 1/2m

Step-by-step explanation:

Given that :

Speed = 2 characters per second

Rate of change = 1/2 character per second increase per month

New texting speed after 1 month :

Initial speed + (change per month * number of months)

2 + 1/2 * 1

= 2 1/2 or 2.5

After 2 months :

Initial speed + (change per month * number of months)

2 + (1/2 * 2)

2 + 1

= 3 characters per second :

After 3 months :

Initial speed + (change per month * number of months)

2 + 1/2 * 3

= 2 + 1.5

= 3.5

For the algebraic equation :

New texting speed, s

Number of months, m

Initial speed + (change per month * number of months)

s = 2 + 1/2 * m

s = 2 + 1/2m

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