To solve this problem you must appy the proccedure shown below:
1. You have the following function given in the problem above:
f(x)=e^2x
2. You can rewrite is:
y=e^2x
3. Interchange the variables, as below:
x=e^2y
3. The inverse of an exponential function is the logarithm function. Thereforem you have:
ln(x)=ln(e^2y)
ln(x)=2y
4.Then, you have:
y=ln(x)/2
Therefore, the answer is:
f^-1(x)=ln(x)/2
ac> bc is always true. This is beacuse c is multiplied to both a and b, and since a> b then ac will have a higher value than bc. Hence ac> bc is always true under the condition a> b.
This is a fun problem! Just graph the two equations, then see what points the line intersects with the parabola. Or, set the two equations equal to each other, and solve for the two intersecting points.
Solve for x and y: -2x+8 = x-2.23y+10.34
This has to be done by hit and trial method. i.e. you have to checking adding which of the function from first column to function in second column will yield h(x).
The following functions yield given value of h(x).
f(x) = -2x + 3
g(x) = 7x - 9
f(x) + g(x) = -2x +3 + 7x - 9
f(x) + g(x) = 5x -6 = h(x)
So, from 1st column its the cell number 3, and from the second column its the cell number 2.
