El máximo común divisor es 12
Por cierto, hablo inglés, así que estoy usando Google Translat. :)
Break the problem into two parts: 1) the area of the this isosceles triangle whose hypotenuse is AB and 2) the area of the semicircle whose diameter is AB.
The triangle is isosceles because the lengths of the two shorter legs are the same (2 meters). Use the Pythagorean Theorem to find the length of the hypotenuse of this triangle. (AB)^2 = (2 m)^2 + (2 m)^2, or 8 m^2. Thus, AB = sqrt(8 m^2), or 2sqrt(2). This AB is also the base of the triangle. What is the area of the triangle?
Next, noting that the diameter AB of the semicircle is 2sqrt(2) and the radius is just sqrt(2), find the area of the semicircle. The area of a circle of radius r
is pi*r^2; here it's pi*(sqrt 2)^2, or pi*2, or 2pi.
Add the area of the triangle to this area of the semicircle (2pi) to find the total area of the figure.
Hint: the area of a triangle is (bh)/2, where h is the height, b is the base.
Answer:
(4,-1)
Step-by-step explanation:
just took the test
Answer:
25 is your answer.
Step-by-step explanation:
Divide 30 by 3 and you will get 10. Divide 30 by 2 and you will get 15. Add 15 to 10 and you get 25 and that is your answer
Hope this is helpful!
