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3 years ago

Please help. if right i will give brainliest

Mathematics

2 answers:

MariettaO [177]3 years ago

3 0

Answer:

m∠7 is equal to 112

Step-by-step explanation:

m∠7 is equal to 112 because m∠2 and m∠7 literally are the same angle

trust me

High Hopes^^

Barry-

almond37 [142]3 years ago

3 0

Answer:

∠ 7 = 112°

Step-by-step explanation:

∠ 2 and ∠ 6 are corresponding angles and congruent, that is

∠ 6 = 112°

∠ 7 and ∠ 6 are vertical angles and congruent, thus

∠ 7 = 112°

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Online jewelry sales have increased steadily over the last 10 years. In 2003, sales were approximately 2 billion dollars, and in

UNO [17]

Answer:

$rate\ of\ increase = 28.8\ billion\ dollars\ per\ year$

model: $y = 28.8(t-2003) + 2$

profit in year 2017: $y = 405.2\ billion\ dollars$

Step-by-step explanation:

The sales increased from 2 billion dollars to 146 billion dollars in five years, so to find the increase in billion dollars per year, we just need to divide the increase by the amount of time:

$rate\ of\ increase = (146 - 2)/5 = 144 / 5 = 28.8\ billion\ dollars\ per\ year$

To construct a model for these sales, we can use the year 2003 as the initial point of a linear equation:

$y = ax + b$

the variable y will represent the profit in billion dollars, the variable x will represent our time, so we can use (t - 2003) in its place to represent the number of years since 2003 (t is the year we want to calculate), the constant 'a' will be our rate of 28.8, and the constant 'b' is the inicial value for the year 2003, that is, 2 (billions). So we have:

$y = 28.8(t-2003) + 2$

In the year 2017, we would have:

$y = 28.8(2017-2003) + 2$

$y = 28.8*14 + 2$

$y = 405.2\ billion\ dollars$

6 0

3 years ago

if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?

Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$