we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
x < -7
Step-by-step explanation:
-4x > 28
-x > 7
x < -7
Answer:
D
Step-by-step explanation:
A negative discriminant indicates that the quadratic equation has no real roots.
Thus the graph does not touch or intersect the x- axis
The only graph that does not touch or intersect the x- axis is the fourth one
Answer:
Step-by-step explanation:
The length of the arc is proportional to the degree measure it in encompasses. Since there are 360 degrees in a circle and the arc is 120 degrees, the arc's length will be 
of the circle's length (circumference).
The circumference of a circle is given by 
, where 
is the radius of the circle. Therefore, the circumference of the circle is 
. As we found earlier, the length of the arc is 
of this circumference. Therefore, the arc's length is 
.
To the nearest integer, this is 
.
