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AURORKA [14]
3 years ago
11

Which statement best describes the area of Triangle ABC shown below

Mathematics
2 answers:
Ratling [72]3 years ago
6 0
Area of triangle = (hb)/2 = (3*2)/2 = 6/2 = 3

area of rectangle = w * l = 2 * 3 = 6
1/2 of 6 = 6/2 = 3

answer is A
Mandarinka [93]3 years ago
3 0
This goes with the first one . it is half the area of a rectangle of side 2 and 3 units
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Which of the following statements about the sampling distribution of the sample mean, x-bar, is not true? A. The sampling distri
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Answer: E. All of the above statements are true

Step-by-step explanation:

The mean of sampling distribution of the mean is simply the population mean from which scores were being sampled. This implies that when population has a mean μ, it follows that mean of sampling distribution of mean will also be μ.

It should also be noted that the distribution's shape is symmetric and normal and there are no outliers from its overall pattern.

The statements about the sampling distribution of the sample mean, x-bar that are true include:

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• The sampling distribution is normal regardless of the sample size, as long as the population distribution is normal. • The sampling distribution's mean is the same as the population mean.

• The sampling distribution's standard deviation is smaller than the population standard deviation.

Therefore, option E is the correct answer as all the options are true.

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What is the correct first step to solve this system of equations by elimination?
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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

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Free plonts have a good day god loves u
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Answer:

God bless you too. hope your having a wonderful day.

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