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3 years ago

What is the GCF of 14 and 21

Mathematics

1 answer:

n200080 [17]3 years ago

8 0

Hey there the answer is,

The Greates Common Factor (GCF) is: 7


Hope I helped!!!<3

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Help! ASAP Giving brainly answer

xxMikexx [17]

Answer: 10ft

Since $\sqrt{90}$ = 9.48 which is 10 when you round it to the nearest ft.

Plz Mark me Brainliest it will mean a lot! :)

7 0

3 years ago

Read 2 more answers

iTunes and Amazon each have plans for downloading music. iTunes charges $5.00 to join and $0.75 per song. Amazon has no fee to j

aleksandrvk [35]

Answer:

20 songs.

Step-by-step explanation:

we are given that, iTunes charges $5.00 to join and $0.75 per song.

Amazon has no fee to join and charges $1.00 per song.

Let x songs would you have to download (same number of downloads for each company) so that the prices are the same.

Then we can write

$5+0.75x=1x\\\text{take like terms together by adding -0.75x on both the sides}\\5+0.75x-0.75x=1x-0.75x\\5=0.25x\\\text{Divide both the sides by 0.25}\\x=20$

7 0

3 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Area of a Rectangle: A = lw

l is length
w is width

Calculus

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle l = 10 \ meters$

$\displaystyle \frac{dl}{dt} = 4 \ m/day$

$\displaystyle w = 23 \ meters$

$\displaystyle \frac{dw}{dt} = 1 \ m/day$

Step 2: Differentiate

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

Step 3: Solve

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$