The volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
<h3>What is the volume of right square pyramid?</h3>
The volume of a square pyramid is expressed as;
V = (1/3)a²h
Where a is the base length and h is the height of the pyramid
Given that;
- Base edges of the square base a = 64cm
- Slant height s = 40cm
- Height of the pyramid h = ?
- Volume = ?
First, we determine the height of the pyramid using Pythagorean theorem.
c² = a² + b²
- c = s = 40cm
- a = half of the base length = a/2 = 64cm/2 = 32cm
- b = h
(40cm) = (32cm)² + h²
1600cm² = 1024cm² + h²
h² = 1600cm² - 1024cm²
h² = 576cm²
h = √576cm²
h = 24cm
Now, we calculate the volume of the right square pyramid;
V = (1/3)a²h
V = (1/3) × (64cm)² × 24cm
V = (1/3) × 409664cm² × 24cm
V = 32768cm³
Therefore, the volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
Learn more about volume of pyramids here: brainly.com/question/27666514
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