Answer: 2c^2
Step by step explanation:
Answer:
7 1/17
Step-by-step explanation:
A figure can be helpful.
The inscribed semicircle has its center at the midpoint of th base. It is tangent to the side of the isosceles triangle, so a radius makes a 90° angle there.
The long side of the isosceles triangle can be found from the Pythagorean theorem to be ...
BC² = BD² +CD²
BC² = 8² +15² = 289
BC = √289 = 17
The radius mentioned (DE) creates right triangles that are similar to ∆BCD. In particular, we have ...
(long side)/(hypotenuse) = DE/BD = CD/BC
DE = BD·CD/BC = 8·15/17
DE = 7 1/17 ≈ 7.059

Hope I helped, also, I used the math thingy, which I haven't used before, so I'm not sure quite how this turned out, well, I guess we will see in a minute! But if it does not work I can try it just typing regularly.
the answer for this question is 3,4and5
Answer:
It's just a simultaneous equation
Step-by-step explanation:
Let a big bag of sugar = x
Let a small bag of flour = y
x+x+y = 12kg
2x+y = 12kg ... 1
x-y = 2kg ... 2
Add 1 and 2
2x+y = 12
+
<u> </u><u> </u><u>x</u><u> </u><u>-</u><u>y</u><u> </u><u>=</u><u> </u><u> </u><u>2</u>
3x = 14
x = 14/3 = <u>4.66</u>
Substitute value of x into 1
2(4.66)+y = 12
9.333 + y = 12
12 - 9.333= 12
y = <u>2</u><u>.</u><u>6</u><u>6</u>
Hope you understand it
And I hope my answer was of help to you.