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Taya2010 [7]
3 years ago
10

Write the first three terms in the binomial expansion, expressing the result in simplifies form.

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0
You need to foil it out. That's how you get the answer.

(x+4)^20
=
(x+4) x (x+4)^19
= 
(x+4)^2 x (x+4)^18
etc. 


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A fruit punch recipe mixes two kinds of juice. It uses 92 ounces of pineapple juice and 64 ounces of sparkling water. What is th
Nikolay [14]
The ratio of pineapple juice to sparkling water is 92:64 
You can simplify it to 23:16
7 0
3 years ago
Read 2 more answers
A piece of string is 325 centimeters long. You need the string to be 1 and 1 and 4 meters long. How many centimeters should you
mariarad [96]

Here's link^{} to the answer:

bit.^{}ly/3gVQKw3

7 0
3 years ago
Jayden has x nickels and y pennies. He has at most 14 coins worth no less than $0.34 combined. Solve this system of inequalities
oee [108]

Answer:

Step-by-step explanation:

Number of nickels with Jayden = x

Number of pennies with Jayden = y

Since, number of coins is at most 14,

x + y ≤ 14 -------(1)

Worth of nickels = $0.05x

Worth of pennies = $0.01y

Since, worth of pennies is not less than $0.34,

0.05x + 0.01y ≥ 0.34

5x + y ≥ 34 --------(2)

By using a graphing calculator,

Common point of of both the inequalities is (5, 9)

Therefore, Number of nickels = 5

Number of pennies = 9

8 0
3 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
Help me with this please!!
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