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riadik2000 [5.3K]
3 years ago
12

The atmosphere flows in large convection currents.

Mathematics
2 answers:
OleMash [197]3 years ago
7 0
B. Warm air rises,and cool air sinks.
Ber [7]3 years ago
3 0

Answer:

The answer is B. Warm air rises, and cool air sinks.

Step-by-step explanation:

During atmospheric convection, heat is transferred as a result of heated air (which is lighter and less dense) rising, and cool air (which is heavier and more dense) sinking beneath the heated air: this movement of heated and cool air produces patterns of circulation known as atmospheric convection currents.

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3(у - 3) - 2(у 4) = 4​
Dennis_Churaev [7]

Answer:

y = 5

Step-by-step explanation:

3(у - 3) - 2(у -4) = 4​

Distribute

3y -9 -2y +8 =4

Combine like terms

y -1 =4

Add 1 to each side

y-1+1 = 4+1

y = 5

3 0
3 years ago
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Please help! I will mark as brainliest IF answer is right. <3
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Domain x belongs to [-4 , 0]

Range y belongs to [-4 , 4]

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Scatter plot question :
natka813 [3]

Answer: A would be the answer

Step-by-step explanation:

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The total budget for a landscaping project was $349.02, and the project called for 42 plants. What is the average cost per plant
nekit [7.7K]

Answer:

$8.31

Step-by-step explanation:

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4 0
3 years ago
Find the probability of at least one
zmey [24]

Answer:

99.8% probability of at least one failure.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of success is 30%.

This means that p = 0.3

Five trials:

This means that n = 5

Find the probability of at least one failure in five trials of a binomial experiment in which the probability of success is 30%.

Less than five sucesses, which is:

P(X < 5) = 1 - P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{0} = 0.002

P(X < 5) = 1 - P(X = 5) = 1 - 0.002 = 0.998

0.998*100% = 99.8%

99.8% probability of at least one failure.

8 0
3 years ago
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