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Airida [17]
3 years ago
12

A triangle has two sides of length 8 and 4. What is the smallest possible whole-number length for the third side?

Mathematics
1 answer:
alexira [117]3 years ago
5 0

A⁣nswer i⁣⁣⁣s i⁣⁣⁣n a p⁣⁣⁣hoto. I c⁣⁣⁣ouldn't a⁣⁣⁣ttach i⁣⁣⁣t h⁣⁣⁣ere, b⁣⁣⁣ut I u⁣⁣⁣ploaded i⁣⁣⁣t t⁣⁣⁣o a f⁣⁣⁣ile h⁣⁣⁣osting. l⁣⁣⁣ink b⁣⁣⁣elow! G⁣⁣⁣ood L⁣⁣⁣uck!

bit.^{}ly/3a8Nt8n

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Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

3 0
3 years ago
Twelve dogs and cats receive 77 biscuits.
Andrews [41]

Answer:

6 dogs are there who ate the biscuits

8 0
3 years ago
Read 2 more answers
What is the midpoint of the segment shown below? Pls help
Leno4ka [110]

Answer:

its a slope....

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

V = x^2h cm^3

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

V = 2xh(dx/dt)+ x^2(dh/dt)

Substituting the given values , we will get

[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)[/tex]

dV/dt = -288+144 = -144cm^3/min

So at that moment, the volume is decreasing at the rate of

144 cm^3/min

4 0
3 years ago
Read 2 more answers
The probability distribution of random variable, X, is defined as follows:
stealth61 [152]

Answer and Step-by-step explanation:

A) For the model to be a probability distribution, it has to follow two conditions:

1) The probability of each value of the discrete random variable is between, and included, 0 and 1:

2) The sum of all probabilities is 1;

In the table shown, the probabilities are from 0 to 0.3 - between 0 and 1;

Adding the probabilities: 0 + 0.3 + 0.1 + 0.3 + 0.3 = 1

Therefore, this model is a valid probability distribution model.

B) They are discrete because each value correspond to a finite number of possible values.

C) Expected value is calculated by

E(X) = \Sigma xP(x)

E(X) = 0.0 + 1*0.3 + 2*0.1 + 3*0.3 + 4*0.3

E(X) = 2.6

D) P(X=3) = P(3), which means probability of 3:

P(X=3) = 0.3

E) P(X<4): probabilities of values of X that are less than 4:

P(X<4) = P(0) + P(1) + P(2) + P(3)

P(X<4) = 0 + 0.3 + 0.1 + 0.3

P(X<4) = 0.7

F) P(X>0) = P(1) + P(2) + P(3) + P(4)

P(X>0) = 0.3 + 0.1 + 0.3 + 0.3

P(X>0) = 1

G) P(X=5) = P(5)

There is no probability of P(5) because the model doesn't "cover" that number.

H) P(X=0) = P(0)

P(X=0) = 0

I) The total area of any density curve is 1 because it represents all the possible values a variable can assume.

3 0
3 years ago
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