All categories

2 years ago

Can Somebody Help Me

Mathematics

1 answer:

Monica [59]2 years ago

4 0

Step-by-step explanation:

Can't see anything

Please be more specific

You might be interested in

The ratio of the side lengths of a quadrilateral is 3:3:5:8, and the perimeter is 380cm. What is the measure of the longest side

castortr0y [4]

Answer:

160

Step-by-step explanation:

Add the ratios together to get the sum of them is 19. Since the perimeter is 380, divide 380 by 19 to get 20.

The shortest side is 3(20) = 60,

the next side is 5(20) = 100, and

the longest side is 8(20) = 160

3 0

2 years ago

Each student on the trip to cooperstown paid the same amount .the tottal amount collected was $589.pilar paid for her ticket usi

professor190 [17]

Answer:

$231.67

Step-by-step explanation:

how you need to divide 589 to 3 and than you get 231.67

5 0

3 years ago

Please help 15 points each but beware if you use my points for no reason I'll report you

romanna [79]

Answer:

$2048~ \text{in}^3$

Step-by-step explanation:

$\text{Volume,}~ V = \dfrac 43 \pi r^3 \\\\\\~~~~~~~~~~~~~~~=\dfrac 43 \times 3 \times 8^3\\\\\\~~~~~~~~~~~~~~~=4 \times 512\\\\\\~~~~~~~~~~~~~~~=2048~ \text{in}^3$

6 0

1 year ago

Read 2 more answers

Write 32.5% as a fraction in simplest form

Thepotemich [5.8K]

I'm pretty sure that the answer is 13/40

5 0

3 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

2 years ago