Answer:
4 UNLESS IM WRONG MAYBE ITS 21
Let <em>s</em> be the plane's speed in still air and <em>w</em> the wind speed. Then
<em>s</em> - <em>w</em> = (6060 km)/(6 h) = 1010 km/h
<em>s</em> + <em>w</em> = (12,150 km)/(9 h) = 1350 km/h
Adding these equations together eliminates <em>w</em> and lets you solve for <em>s</em> :
(<em>s</em> - <em>w</em>) + (<em>s</em> + <em>w</em>) = 1010 km/h + 1350 km/h
2<em>s</em> = 2360 km/h
<em>s</em> = 1180 km/h
Yes you do because you cannot subtract 7 from 6.
Answer:
i would say that the rocket was in the air for 8 seconds and the highest it went in the air was 48
Step-by-step explanation: