The first answer is the correct one
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Answer:
hmm a chicken
Step-by-step explanation:
Answer:
D
x=-4+2√2 or x=-4-2√2
Step-by-step explanation:
3(x+4)²-24
3(x+4)²=24
(x+4)²=24/3
(x+4)²=8
x+4=√8
x+4=±2√2
x=-4+2√2 or x=-4-2√2
Answer:
y=3x +25
Step-by-step explanation:
First calculate the slope:
m = (y1 - y2)/(x1-x2)
m = (49 - 13)/(8-(-4))
m= 36/12 = 3
so we have
y = 3x + b
subtitute a point:
49=3(8) + b
b=25
the equation is y=3x +25
