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arlik [135]
3 years ago
15

Find three consecutive positive integers such that the product of the first and​ third, minus the​ second, is 1 more than 7 time

s the third.
Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0
--------------------------------------------------------------------
Define x :
--------------------------------------------------------------------
Let the smallest number be x.
First number = x
Second Number = x + 1
Third Number = x + 2

--------------------------------------------------------------------
Construct equation :
--------------------------------------------------------------------
x(x+2) - (x+1) = 7(x+2) + 1

--------------------------------------------------------------------
Solve x :
--------------------------------------------------------------------
x(x + 2) - (x + 1) = 7(x + 2) + 1
x² + 2x - x - 1 = 7x + 14 + 1
x²- 6x - 16 = 0
<span>(x+2)(x-8) = 0
</span>x = -2 or x = 8

Since x is a positive integer, it cannot be negative.
⇒x = 8

--------------------------------------------------------------------------
Answer: The three numbers are 8, 9 and 10.
--------------------------------------------------------------------------
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An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
2/3, 24%, 0.61 least to greasiest
Semmy [17]
24% .61 2/3 two thirds is .66 24% is .24 and .61 is .61
4 0
3 years ago
Help I need help please
s344n2d4d5 [400]

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b) Positive correlation

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Scattered points on the scatter plot make no relationship.

4 0
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There are 45 exotic fish in a fish tank. 9 of those fish are clown fish. What percent of the fish in the tank are clown fish.
Marrrta [24]
Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

(value/total value)×100%.

So,
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Answer= 20%
6 0
3 years ago
How do I make the table? With what numbers?
zaharov [31]
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4 0
3 years ago
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