Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 7 time

Question

arlik [135]

3 years ago

15

Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 7 time

s the third.

Mathematics

1 answer:

Bas_tet [7] · Answer 1 · 2022-07-04T06:34:53+03:00

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Define x :
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Let the smallest number be x.
First number = x
Second Number = x + 1
Third Number = x + 2

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Construct equation :
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x(x+2) - (x+1) = 7(x+2) + 1

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Solve x :
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x(x + 2) - (x + 1) = 7(x + 2) + 1
x² + 2x - x - 1 = 7x + 14 + 1
x²- 6x - 16 = 0
<span>(x+2)(x-8) = 0
</span>x = -2 or x = 8

Since x is a positive integer, it cannot be negative.
⇒x = 8

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Answer: The three numbers are 8, 9 and 10.
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Find three consecutive positive integers such that the product of the first and​ third, minus the​ second, is 1 more than 7 time

Find three consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 7 time