Question

What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfraction endroot? assume x ≠ 0.

Answer 1

The simplified form of the given equation is $=\frac{6}{5x^{10}}$

We have given that,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

Apparently, you want to simplify the given equation,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

 

The applicable rules of exponents are,

What is the exponent rule?

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^(-b)

 (a^b)^c = a^(bc)

So the expression simplifies as

 $=\sqrt{\frac{72x^{16}}{50x^{36} }}\\\\=\frac{6}{5x^{10}}$

Therefore the simplified form of the given equation is $=\frac{6}{5x^{10}}$

To learn more about exponential form visit:

brainly.com/question/1269112

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