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satela [25.4K]
2 years ago
6

One third of all guitars that are sold in the shop is a Stratocaster, one fourth of them are Telecasters, and one fifth of them

is a Les Paul. If Jamie goes and buys a guitar, what are the chances she gets a telecaster or a Les Paul?
A. 58%
B. 53%
C. 45%
D. 43%
Mathematics
1 answer:
marin [14]2 years ago
3 0

The probability that Jamie buys a telecaster or a Less Paul is 45% or forty-five percent.

<h3>How to find out the probability?</h3>

1. Find the individual probabilities:

Probabilities to buy a telecaster:

  • 1/ 4 = 0.25

Probabilities to buy a Les Paul:

  • 1/ 5 = 0.2

2. Add the probabilities:

  • 0.25 + 0.2 = 0.45

3. Multiply by 100:

  • 0.45 x 100 = 45%

Learn more about percentage in: brainly.com/question/13450942

#SPJ1

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Shtirlitz [24]
B.
For all 3 to work together, they can paint 1 room per hour.
C.
John can paint a room at 1/4 of a room per hour.
Rick can paint a room at 1/5 of a room per hour.
Together they can paint a room at a rate of 9/20 of rooms per hour.
D.
1 = 1/4j + 1/5r + 11/20m (john, rick, molli)
E. 
The least common denominator is 20
F. 
1 = 1/4(0) + 1/5(0) + 11/20x
1 = 0 + 0 + 11/20x
1 = 11/20x
x = 1/(11/20)
x = 1 9/11 
It will take Molli 1 hour and 49 minutes (60 x 9/11) to paint the room alone.
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Least to greatest -5, -5.2, 5.5, -5 1/2, -5/2
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We can visualize a number line to see where these numbers would rank.

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Miguel drives 295 miles in 5 hours. How many miles does Miguel drive in 75 points
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3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
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