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dem82 [27]
2 years ago
9

Pls help i dont know ?

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
5 0

Answer:

8 \times(2+15)

Step-by-step explanation:

Juliette [100K]2 years ago
5 0

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to write "8 times the sum of 2 and 15" as an algebraic expression.

\triangle~\fbox{\bf{KEY:}}

  • "sum" means add

So, we add 2 and 15:

\mathtt{2+15}

Now we multiply 8 times this expression:

\mathtt{8\times(2+15)}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

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At the movie theatre, child admission is $6.40 and adult admission is $9.90. On Friday, 154 tickets were sold for a total sales
Minchanka [31]
6.40x+9.90(154-x)=1230.90
Solve for x
X=84 for child

154-84=70 for adults
4 0
3 years ago
How to find the equation?
bixtya [17]

Answer:

y = 2x + 60

Step-by-step explanation:

Use the equation for a line: y = mx + b

Where

x and y are points on the graph

and m is the slope, and can be found by finding \frac{rise}{run}


so the slope is 10/5 or 2, since the graph goes up by 10 and over by 5.

so plug into the equation, and you get y = 2x + b

Next, pick a point on the graph, and plug in the x and y coordinates,

for example:

(x,y) = (5,70)

so, 70 = 2(5) + b

then solve for b

60 = b

Then rewrite the equation

y = 2x + 60

4 0
3 years ago
I need help with this also I had was to repost it again because someone deleted it
igomit [66]

Answer: 8:05

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
If I don't read carefully, I often make mistakes on my work.
velikii [3]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the taylor polynomial t3(x) for the function f centered at the number
inysia [295]

Answer:

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

Step-by-step explanation:

We are given that

f(x)=7tan^{-1}(x)

a=1

T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}

Substitute n=3 and a=1

t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}

f(x)=7tan^{-1}(x)

f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}

Where tan^{-1}(1)=\frac{\pi}{4}

f'(x)=\frac{7}{1+x^2}

Using the formula

\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}

f'(1)=\frac{7}{2}

f''(x)=\frac{-14x}{(1+x^2)^2}

f''(1)=-\frac{7}{2}

f''(x)=-14x(x^2+1)^{-2}

f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})

By using the formula

(uv)'=u'v+v'u

f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}

f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}

f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}

Substitute the values

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

7 0
3 years ago
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