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2 years ago

Ignoring friction, what is the acceleration of a 75.0 kg object which is acted upon by an

Physics

1 answer:

natulia [17]2 years ago

3 0

Explanation:

we can use the formula F = ma

hence,

500 = 75a

a = 6.666 m/s² or 6(2/3) m/s²

hope this helps.

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A car traveled 140 km in 2.5 hours. What was its average speed in km per hour?

Vilka [71]

<h3>formula of speed is distance/time</h3><h3>so</h3><h2>140/2.5</h2><h2>= 56</h2><h2>the answer should be </h2><h2>56 km/h</h2>

5 0

3 years ago

What colors of light are absorbed when white light falls on a green object?

Ipatiy [6.2K]

I'm doing this test later today so I'll let you know the answer

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3 years ago

Read 2 more answers

The shortest pipe in a particular organ is 1.23 m.

AVprozaik [17]

Answer:

The 9th harmonic is 1,010.67 Hz.

Explanation:

Given;

length of the pipe, L = 1.23 m

speed of sound at 0°C = 331.5 m/s

A pipe closed at one end is known as a closed pipe;

The wavelength of the sound for the first harmonic is calculated as;

L = Node ------ > Antinode

$L = \frac{\lambda }{4} \\\\\lambda = 4L$

First harmonic: $F_0 = \frac{V}{\lambda} = \frac{V}{4L}$

The wavelength of the sound for the first harmonic is calculated;

L = Node ----> Node + Node ------> Antinode

$L = \frac{\lambda}{2} + \frac{\lambda}{4} = \frac{2\lambda+\lambda}{4} = \frac{3\lambda}{4} \\\\\lambda = \frac{4 L}{3}$

Second harmonic: $F_1 = \frac{V}{\lambda} = \frac{3V}{4L}$

F₁ = 3F₀

The increment from F₀ to F₁ is 1 to 3; (odd number).

(1, 3, 5, 7, 9, 11, 13, 15, 17, 19..... n+2, where n is odd number)

The 9th harmonic = F₈

F₈ = 15F₀

$F_8= 17(F_0) = 15 (\frac{V}{4L} )\\\\F_8 = 15(\frac{331.5}{4\times 1.23} )\\\\F_8 = 1,010.67 \ Hz$

Therefore, the 9th harmonic is 1,010.67 Hz.

8 0

3 years ago

Why did donald hings invent the walkie talkie ?

Bumek [7]

The "walkie-talkie" is Don Hings' most well-known invention. The earliest versions of this device were designed as portable field radios for the bush pilots of Consolidated Mining and Smeltin , who had to fly their planes between remote sites in the far north of Canada.

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3 years ago

A running shoe company wants to sponsor the fastest 5% of runners. You know that in this race, the running times are normally di

pogonyaev

Answer:

We need a time of 8.118 minutes or higher in order to be sponsored by the company

Explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the running times of a population, and for this case we know the distribution for X is given by:

$X \sim N(7.2,0.56)$

Where $\mu=7.2$ and $\sigma=0.56$ minutes.

And we want the fastest 5% of runners, so we need a value a such that:

$P(X>a)=0.05$ or $P(X$

We need on the right tail of the distribution a value a that gives to us 95% of the area below and 5% of the area above. Both conditions are equivalent.

Let's use the condition $P(X$ , the best way to solve this problem is using the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

So we need a value from the normal standard distribution that accumulates 0.95 of the area on the left and 0.05 on the right. This value on this case is 1.64 and we can founded with the following code in excel:

"=NORM.INV(0.95,0,1)"

If we apply the z score formula to our case we have this:

$P(X$

So then based on the equalities we have this:

$\frac{a-7.2}{0.56}=1.64$

And if we solve for a we got:

$a=(0.56*1.64) +7.2=8.118$

So then we need a time of 8.118 minutes or higher in order to be sponsored by the company

4 0

3 years ago