Answer with Explanation:
We are given that
Mass of squirrel,m=530 g=![\frac{530}{1000}=0.530 kg](https://tex.z-dn.net/?f=%5Cfrac%7B530%7D%7B1000%7D%3D0.530%20kg)
1kg=1000 g
Area=A=![935 cm^2=935\times 10^{-4} m^2](https://tex.z-dn.net/?f=935%20cm%5E2%3D935%5Ctimes%2010%5E%7B-4%7D%20m%5E2)
![1 cm^2=10^{-4} m^2](https://tex.z-dn.net/?f=1%20cm%5E2%3D10%5E%7B-4%7D%20m%5E2)
Height,h=4.4 m
C=1
![\rho=1.21 kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D1.21%20kg%2Fm%5E3)
Width of rectangular prism,b=11.6 cm=![\frac{11.6}{100}=0.116 m](https://tex.z-dn.net/?f=%5Cfrac%7B11.6%7D%7B100%7D%3D0.116%20m)
1 m=100 cm
Length,l=23.2 cm=![0.232 m](https://tex.z-dn.net/?f=0.232%20m)
Area=![l\times b=0.116\times 0.232=0.0269 m^2](https://tex.z-dn.net/?f=l%5Ctimes%20b%3D0.116%5Ctimes%200.232%3D0.0269%20m%5E2)
Terminal velocity,![v_t=\sqrt{\frac{2mg}{\rho CA}}](https://tex.z-dn.net/?f=v_t%3D%5Csqrt%7B%5Cfrac%7B2mg%7D%7B%5Crho%20CA%7D%7D)
Where ![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
Using the formula
![v_t=\sqrt{\frac{2\times 0.530\times 9.8}{1.21\times 1\times 0.0269}}](https://tex.z-dn.net/?f=v_t%3D%5Csqrt%7B%5Cfrac%7B2%5Ctimes%200.530%5Ctimes%209.8%7D%7B1.21%5Ctimes%201%5Ctimes%200.0269%7D%7D)
![v_t=17.86 m/s](https://tex.z-dn.net/?f=v_t%3D17.86%20m%2Fs)
The velocity of person,![v=\sqrt{2gh}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D)
Using the formula
![v=\sqrt{2\times 9.8\times 4.4}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%204.4%7D)
![v=9.29 m/s](https://tex.z-dn.net/?f=v%3D9.29%20m%2Fs)
Answer:
lead with Z = 82 is transformed into Bismuth with Z = 73
The Po with Z = 84 becomes Pb with Z = 82
Explanation:
Beta decay occurs when a neutron emits an electron and an anti neutrino from the atomic nucleus, therefore the atomic number of the material increases by one unit.
Pb + e + ν → Bi
lead with Z = 82 is transformed into Bismuth with Z = 73
In alpha decay, a helium nucleus is emitted from the nucleus of the atom, therefore the atomic number decreases by two units.
Po +α → Pb
The Po with Z = 84 becomes Pb with Z = 82
Answer:
The average recoil force on the gun during that 0.40 s burst is 45 N.
Explanation:
Mass of each bullet, m = 7.5 g = 0.0075 kg
Speed of the bullet, v = 300 m/s
Time, t = 0.4 s
The change in momentum of an object is equal to impulse delivered. So,
![F\times t=mv\\\\F=\dfrac{mv}{t}](https://tex.z-dn.net/?f=F%5Ctimes%20t%3Dmv%5C%5C%5C%5CF%3D%5Cdfrac%7Bmv%7D%7Bt%7D)
For 8 shot burst, average recoil force on the gun is :
![F=\dfrac{8mv}{t}\\\\F=\dfrac{7.5}{1000}\cdot\dfrac{300}{0.4}\cdot8\\\\F=45\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B8mv%7D%7Bt%7D%5C%5C%5C%5CF%3D%5Cdfrac%7B7.5%7D%7B1000%7D%5Ccdot%5Cdfrac%7B300%7D%7B0.4%7D%5Ccdot8%5C%5C%5C%5CF%3D45%5C%20N)
So, the average recoil force on the gun during that 0.40 s burst is 45 N.
The Impulse delivered to the baseball is 89 kgm/s.
To solve the problem above, we use the formula of impulse.
⇒ Formula:
- I = m(v-u)................. Equation 1
Where:
- I = Impulse delivered to the baseball
- m = mass of the baseball
- v = Final velocity of the baseball
- u = initial speed of the baseball
From the question,
⇒ Given:
- m = 0.8 kg
- u = 67 m/s
- v = -44 m/s
⇒ Substitute these values into equation 1
- I = 0.8(-44-67)
- I = 0.8(-111)
- I = -88.8
- I ≈ -89 kgm/s
Note: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.
Hence, The Impulse delivered to the baseball is 89 kgm/s.
Learn more about impulse here: brainly.com/question/7973509