1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
2 years ago
8

What is electromagnetic induction?​

Physics
2 answers:
dlinn [17]2 years ago
4 0

Answer:

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

Explanation:

correct me if im wrong:)

gulaghasi [49]2 years ago
3 0
  • The phenomenon of generation of current or emf by changing the magnetic flux is known as Electromagnetic Induction.

  • First Law Whenever magnetic flux linked with the closed loop or circuit changes, an emf induces in the loop or circuit which lasts so long as change in flux continuous.

Explanation:

Hope it helps~

You might be interested in
Help, It has multiple answers for this question.
evablogger [386]
The answer is ultra violet radiation. From the air
4 0
3 years ago
If a net force of 250 N causes an object to accelerate at 20m/s^2 what must its mass be?
aleksandr82 [10.1K]
The answer is 12.5 kg because 250N / 20m/s^2

I hope that helped
7 0
3 years ago
A uniform disk with mass 35.2 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is stati
Sergio [31]

Answer:

a) v = 1.01 m/s

b) a = 5.6 m/s²

Explanation:

a)

  • If the disk is initially at rest, and it is applied a constant force tangential to the rim, we can apply the following expression (that resembles Newton's 2nd law, applying to rigid bodies instead of point masses) as follows:

       \tau = I * \alpha  (1)

  • Where τ is the external torque applied to the body, I is the rotational inertia of the body regarding the axis of rotation, and α is the angular acceleration as a consequence of the torque.
  • Since the force is applied tangentially to the rim of the disk, it's perpendicular to the radius, so the torque can be calculated simply as follows:
  • τ = F*r (2)
  • For a solid uniform disk, the rotational inertia regarding an axle passing through its center  is just I = m*r²/2 (3).
  • Replacing (2) and (3) in (1), we can solve for α, as follows:

       \alpha = \frac{2*F}{m*r} = \frac{2*34.5N}{35.2kg*0.2m} = 9.8 rad/s2 (4)

  • Since the angular acceleration is constant, we can use the following kinematic equation:

        \omega_{f}^{2}  - \omega_{o}^{2} = 2*\Delta \theta * \alpha (5)

  • Prior to solve it, we need to convert the angle rotated from revs to radians, as follows:

       0.2 rev*\frac{2*\pi rad}{1 rev} = 1.3 rad (6)

  • Replacing (6) in (5), taking into account that ω₀ = 0 (due to the disk starts from rest), we can solve for ωf, as follows:

       \omega_{f} = \sqrt{2*\alpha *\Delta\theta} = \sqrt{2*1.3rad*9.8rad/s2} = 5.1 rad/sec (7)

  • Now, we know that there exists a fixed relationship the tangential speed and the angular speed, as follows:

        v = \omega * r (8)

  • where r is the radius of the circular movement. If we want to know the tangential speed of a point located on the rim of  the disk, r becomes the radius of the disk, 0.200 m.
  • Replacing this value and (7) in (8), we get:

       v= 5.1 rad/sec* 0.2 m = 1.01 m/s (9)

b)    

  • There exists a fixed relationship between the tangential and the angular acceleration in a circular movement, as follows:

       a_{t} = \alpha * r (9)

  • where r is the radius of the circular movement. In this case the point is located on the rim of the disk, so r becomes the radius of the disk.
  • Replacing this value and (4), in (9), we get:

       a_{t}  = 9.8 rad/s2 * 0.200 m = 1.96 m/s2 (10)

  • Now, the resultant acceleration of a point of the rim, in magnitude, is the vector sum of the tangential acceleration and the radial acceleration.
  • The radial acceleration is just the centripetal acceleration, that can be expressed as follows:

       a_{c} = \omega^{2} * r  (11)

  • Since we are asked to get the acceleration after the disk has rotated 0.2 rev, and we have just got the value of the angular speed after rotating this same angle, we can replace (7) in (11).
  • Since the point is located on the rim of the disk, r becomes simply the radius of the disk,, 0.200 m.
  • Replacing this value and (7) in (11) we get:

       a_{c} = \omega^{2} * r   = (5.1 rad/sec)^{2} * 0.200 m = 5.2 m/s2 (12)

  • The magnitude of the resultant acceleration will be simply the vector sum of the tangential and the radial acceleration.
  • Since both are perpendicular each other, we can find the resultant acceleration applying the Pythagorean Theorem to both perpendicular components, as follows:

       a = \sqrt{a_{t} ^{2} + a_{c} ^{2} } = \sqrt{(1.96m/s2)^{2} +(5.2m/s2)^{2} } = 5.6 m/s2 (13)

6 0
3 years ago
All ions are atoms with a
Cloud [144]
All ions are atoms with a charge
3 0
3 years ago
If grade 7 students learn six periods and if one period is 40 minutes then how many seconds they learn per day
Ludmilka [50]

Answer:

C. 14400

Explanation:

40min × 6 periods = 240mins total.

1 minute = 60 seconds.

240 minutes × 60 = 14400 seconds.

6 0
3 years ago
Read 2 more answers
Other questions:
  • Two identical conducting spheres, A and B, carry equal charge. They are stationary and are separated by a distance much larger t
    9·1 answer
  • Titan is the only moon in the solar system with a significant atmosphere. which planet does titan orbit?
    13·1 answer
  • Boss tweed encourage his associates to work like a well oiled machine thus providing his workers with
    15·2 answers
  • A conclusion is a possible answer to a question. True or False?
    15·2 answers
  • Freshly picked cucumbers are dropped into a bin from a height of 1.25 m above the bottom of the bin. Assuming that the bin is em
    11·1 answer
  • Will give brainliest!!
    6·1 answer
  • At what efficiency is a photovoltaic array running if insolation on the collector is 650 W/m2, the total collector area is 10 m2
    15·1 answer
  • a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box
    9·1 answer
  • 7. A student is rotating an object on a rope that is 4.5m long. If we increase the length
    5·1 answer
  • Please help!! Physics homework
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!