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salantis [7]
3 years ago
13

Why did donald hings invent the walkie talkie ?

Physics
1 answer:
Bumek [7]3 years ago
3 0
The "walkie-talkie" is Don Hings' most well-known invention. The earliest versions of this device were designed as portable field radios for the bush pilots of Consolidated Mining and Smeltin , who had to fly their planes between remote sites in the far north of Canada.
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What is the current in a circuit with a 4.5 V battery and a 9 Ω resistor?
horsena [70]

Answer:

V=I×R

<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

3 0
3 years ago
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NEED HELP NOW!!! I WILL BRAINLIEST.
Sergio039 [100]

Answer:

1. Carbon-12

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3. Carbon-13

7 0
3 years ago
A force of 50 N stretches a string by 4 cm,calculate the elastic constant.
murzikaleks [220]

Answer:

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8 0
3 years ago
If a car changes its velocity from 32 km/hr to 54 km/hr in 8.0 seconds, what is its acceleration?
Stella [2.4K]
Use the equation for the acceleration
A = final velocity - initial velocity divided by time final - time initial
A= 54 - 32 / 8 - 0
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Hope this helps!
3 0
3 years ago
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The two masses in the Atwood's machine shown in the figure are initially at rest at the same height. After they are released, th
Inga [223]

According to the description given in the photo, the attached figure represents the problem graphically for the Atwood machine.

To solve this problem we must apply the concept related to the conservation of energy theorem.

PART A ) For energy conservation the initial kinetic and potential energy will be the same as the final kinetic and potential energy, so

E_i = E_f

0 = \frac{1}{2} (m_1+m_2)v_f^2-m_2gh+m_1gh

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

PART B) Replacing the values given as,

h= 1.7m\\m_1 = 3.5kg\\m_2 = 4.3kg \\g = 9.8m/s^2 \\

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

v_f = \sqrt{2(9.8)(1.7)(\frac{4.3-3.5}{3.5+4.3})}

v_f = 1.8486m/s

Therefore the speed of the masses would be 1.8486m/s

6 0
4 years ago
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