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ra1l [238]
3 years ago
5

Nitromethane (ch3no2) burns in air to produce significant amounts of heat. 2 ch3no2(l) + 3 2 o2( g) ¡ 2 co2( g) + 3 h2o(l) + n2

( g) δh° rxn= -1418 kj how much heat is produced by the complete reaction of 5.56 kg of nitromethane
Physics
2 answers:
ANEK [815]3 years ago
6 0

From the balanced reaction, we are given that 1418 kJ of heat is released for every 2 moles of nitromethane (CH3NO2) reacted.

So first calculate the moles of CH3NO2:

moles CH3NO2 = 5560 g / (61.04 g/mol)

moles CH3NO2 = 91.1 mol

 

So total heat released is:

total heat = (-1418 kJ / 2mol) * 91.1 mol

<span>total heat = -129,162.52 kJ = -129.16 MJ</span>

frozen [14]3 years ago
3 0

Answer:

6.46 x 10^4 kJ

Explanation:

Calculate moles of CH3NO2:

kg to g:

5.56 kg  x 1000 = 5560 g

molar mass of CH3NO2:

12.01 + 3.024 + 14.01 + 32.00 = 61.04 g

moles= mass / molar mass

moles = 5560 g / 61.04 g/ mol

moles = 91.1

Then calculate total heat

Total heat = (delta H / 2 mol) x moles of CH3NO2

Plug into calculator just like this

Total heat = (-1418/2) x 91.1

Total heat = 64589.9 kJ

move the decimal over 4 places:

6.46 x 10^4 kJ is the result

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so we will have

32.5(900)(45.8 - T) = 105.3(4186)(T - 15.4)

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so we have

16.1 T = 277.87

T = 17.26 ^oC

6 0
3 years ago
To boil water it requires heat , what happens to the heat when the water cools down as energy can neither be destroyed nor be cr
skelet666 [1.2K]

Answer:

Explanation:

The water particles just flow through each other. They cannot be destroyed nor created.

4 0
3 years ago
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A 5 kg ball is sitting on the floor without moving. What is the momentum of the ball?
natita [175]

Answer:

The ball has no momentum

Explanation:

The given parameters are;

The mass of the ball = 5 kg

The velocity of the ball = 0 (The ball is sitting on the floor without moving)

The momentum of the ball = The mass of the ball × Velocity of the ball

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5 0
2 years ago
A bus hits a bug and the bug splatters on the windshield, which force is greater?
grandymaker [24]

The forces acting on a body and the type of motion that results are given by Newton's three Laws of motion

  • The <u>force </u>of the bus is <u>the same</u> as reactive force of the bug

Reason:

According to Newton's third Law of motion, given that the bug collides

with the bus, the force with which the bus hits the bug is equal to the

reactive force of the bug on the on the bus

According to Newton's second Law of motion, force is equal to the rate of

change of the momentum produced

The impulse of the force of the bus on the bug is given as follows;

F·Δt = m·(v₂ - v₁)

Given that the force of the bus is large, the change in momentum, m·(v₂ - v₁),

is also large such that the parts of the bug are split by the rapid change in

velocity, and the bug splatters on the windshield, and is then carried along

on the trip,

The equally large reactive force of the bug, is such that the bug splatters

due its magnitude

Therefore, the correct response is that <u>the forces are the same</u>

Lean more here:

brainly.com/question/21279060

8 0
2 years ago
the average american receives 2.28 mSv dose equivalent from radon each year. Assuming you receive this dose, and it all comes fr
Dmitry [639]

Answer:

The approximate number of decays  this represent  is  N= 23*10^{10}  

Explanation:

 From the question we are told that

    The amount of Radiation received by an average american is I_a = 2.28 \ mSv

     The source of the radiation is S = 5.49 MeV \ alpha \ particle

 Generally

            1 \  J/kg = 1000 mSv

   Therefore  2.28 \ mSv = \frac{2.28}{1000} = 2.28 *10^{-3} J/kg

Also  1eV = 1.602 *10^{-19}J

  Therefore  2.28*10^{-3} \frac{J}{kg} = 2.28*10^{-3} \frac{J}{kg}  * \frac{1ev}{1.602*10^{-19} J} = 1.43*10^{16} ev/kg

           An Average american weighs 88.7 kg

      The total energy received is mathematically evaluated as

        1 kg ------> 1.423*10^{16}ev \\88.7kg  --------> x

Cross-multiplying and making x the subject

           x = 88.7 * 1.423*10^{16} eV

              x = 126.2*10^{16}eV

Therefore the total  energy  deposited is x = 126.2*10^{16}eV

The approximate number of decays  this represent  is mathematically evaluated as

            N = \frac{x}{S}

Where n is the approximate number of decay

   Substituting values

                             N = \frac{126 .2*10^{16}}{5.49*10^6}  

                                  N= 23*10^{10}  

                     

             

7 0
3 years ago
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