Work is force*displacement if the force and displacement is parallel.
a. You can average the force over the distance so W = Fave*d
<span>b The force part of that multiplication is zero. </span>
<span>c. You can form the average force for the interval from 2 to 3 and find the work for that section and then consider the interval from 3 to 4, find the work and add the 2 work results.
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Answer:
83.3 Wb
Explanation:
The magnetic flux linkage through the coil is given by:

where
B is the magnetic field strength
A is the cross sectional area
N is the number of turns in the coil
is the angle between the direction of the field and the normal to the coil
In this problem:
B = 1.74 T
A = 0.133 m^2
N = 360

Therefore, the magnetic flux linkage is

First of all the kinetic energy is when the particles move in continuous random motion.
If the temperature is high the colliding particles will collide more. and if the temperature is low the colliding particles will collide less.
Low temperature result in low kinetic energy
High temperature result in high kinetic energy
Absolute zero is the point where where all molecules have no kinetic energy. It is a theoretical value (it has never been reached).
The Kelvin temperature scale is based on absolute zero being the lowest possible temperature that could theoretically be reached. That is why there is no such thing as a negative Kelvin temperature value.
Explanation:
(a) Hooke's law:
F = kx
7.50 N = k (0.0300 m)
k = 250 N/m
(b) Angular frequency:
ω = √(k/m)
ω = √((250 N/m) / (0.500 kg))
ω = 22.4 rad/s
Frequency:
f = ω / (2π)
f = 3.56 cycles/s
Period:
T = 1/f
T = 0.281 s
(c) EE = ½ kx²
EE = ½ (250 N/m) (0.0500 m)²
EE = 0.313 J
(d) A = 0.0500 m
(e) vmax = Aω
vmax = (0.0500 m) (22.4 rad/s)
vmax = 1.12 m/s
amax = Aω²
amax = (0.0500 m) (22.4 rad/s)²
amax = 25.0 m/s²
(f) x = A cos(ωt)
x = (0.0500 m) cos(22.4 rad/s × 0.500 s)
x = 0.00919 m
(g) v = dx/dt = -Aω sin(ωt)
v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)
v = -1.10 m/s
a = dv/dt = -Aω² cos(ωt)
a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)
a = -4.59 m/s²
Answer:
Check attachment for your answer
Good luck