1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ra1l [238]
3 years ago
5

Nitromethane (ch3no2) burns in air to produce significant amounts of heat. 2 ch3no2(l) + 3 2 o2( g) ¡ 2 co2( g) + 3 h2o(l) + n2

( g) δh° rxn= -1418 kj how much heat is produced by the complete reaction of 5.56 kg of nitromethane
Physics
2 answers:
ANEK [815]3 years ago
6 0

From the balanced reaction, we are given that 1418 kJ of heat is released for every 2 moles of nitromethane (CH3NO2) reacted.

So first calculate the moles of CH3NO2:

moles CH3NO2 = 5560 g / (61.04 g/mol)

moles CH3NO2 = 91.1 mol

 

So total heat released is:

total heat = (-1418 kJ / 2mol) * 91.1 mol

<span>total heat = -129,162.52 kJ = -129.16 MJ</span>

frozen [14]3 years ago
3 0

Answer:

6.46 x 10^4 kJ

Explanation:

Calculate moles of CH3NO2:

kg to g:

5.56 kg  x 1000 = 5560 g

molar mass of CH3NO2:

12.01 + 3.024 + 14.01 + 32.00 = 61.04 g

moles= mass / molar mass

moles = 5560 g / 61.04 g/ mol

moles = 91.1

Then calculate total heat

Total heat = (delta H / 2 mol) x moles of CH3NO2

Plug into calculator just like this

Total heat = (-1418/2) x 91.1

Total heat = 64589.9 kJ

move the decimal over 4 places:

6.46 x 10^4 kJ is the result

You might be interested in
The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. (a) 0 to 1.0 m,
Lina20 [59]
Work is force*displacement if the force and displacement is parallel. 


a. You can average the force over the distance so W = Fave*d 

<span>b The force part of that multiplication is zero. </span>

<span>c. You can form the average force for the interval from 2 to 3 and find the work for that section and then consider the interval from 3 to 4, find the work and add the 2 work results.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
5 0
3 years ago
What is the magnetic flux linkage, in units of Weber, for a coil of 360 turns and cross sectional area of 0.133 m^2 when the mag
zalisa [80]

Answer:

83.3 Wb

Explanation:

The magnetic flux linkage through the coil is given by:

N\phi = BAN sin \theta

where

B is the magnetic field strength

A is the cross sectional area

N is the number of turns in the coil

\theta is the angle between the direction of the field and the normal to the coil

In this problem:

B = 1.74 T

A = 0.133 m^2

N = 360

\theta=90^{\circ}

Therefore, the magnetic flux linkage is

N\phi = (1.74 T)(0.133 m^2)(360) sin 90^{\circ}=83.3 Wb

7 0
3 years ago
How does approaching a temperature of absolute zero affect kinetic energy.?
Alexus [3.1K]

First of all the kinetic energy is when the particles move in continuous random motion.

If the temperature is high the colliding particles will collide more. and if the temperature is low the colliding particles will collide less.

Low temperature result in low kinetic energy 
High temperature result in high kinetic energy

Absolute zero is the point where where all molecules have no kinetic energy. It is a theoretical value (it has never been reached).

The Kelvin temperature scale is based on absolute zero being the lowest possible temperature that could theoretically be reached. That is why there is no such thing as a negative Kelvin temperature value.

7 0
3 years ago
Arrow_forward
garri49 [273]

Explanation:

(a) Hooke's law:

F = kx

7.50 N = k (0.0300 m)

k = 250 N/m

(b) Angular frequency:

ω = √(k/m)

ω = √((250 N/m) / (0.500 kg))

ω = 22.4 rad/s

Frequency:

f = ω / (2π)

f = 3.56 cycles/s

Period:

T = 1/f

T = 0.281 s

(c) EE = ½ kx²

EE = ½ (250 N/m) (0.0500 m)²

EE = 0.313 J

(d) A = 0.0500 m

(e) vmax = Aω

vmax = (0.0500 m) (22.4 rad/s)

vmax = 1.12 m/s

amax = Aω²

amax = (0.0500 m) (22.4 rad/s)²

amax = 25.0 m/s²

(f) x = A cos(ωt)

x = (0.0500 m) cos(22.4 rad/s × 0.500 s)

x = 0.00919 m

(g) v = dx/dt = -Aω sin(ωt)

v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)

v = -1.10 m/s

a = dv/dt = -Aω² cos(ωt)

a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)

a = -4.59 m/s²

3 0
3 years ago
a concave mirror of radius of curvature 20cm produces an inverted image three times the size of an object placed on and perpendi
Elis [28]

Answer:

Check attachment for your answer

Good luck

6 0
3 years ago
Other questions:
  • Why is it impossible for us to observe any furthur than 13.7 billion light years in the universe??
    9·1 answer
  • (a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500-μC charge and flies due west at a spee
    5·1 answer
  • Which group of stars is represented by the line image
    10·2 answers
  • A circuit has a resistance of 2.5 Ω and is powered by a 12.0 V battery.
    7·1 answer
  • During the process of cellular respiration water becomes oxygen
    6·2 answers
  • Solve this question plz
    8·1 answer
  • What is air resistance means explain it with free falling body​
    10·1 answer
  • What describes the main benefit to organisms that reproduce sexually?
    10·2 answers
  • Cork has a density of about 0.60 g/cm3 . Cork will partially float in water which has a density of 1.0 g/cm3 . If the piece of c
    7·1 answer
  • Explain the steps of electric power transmission
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!