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2 years ago

9. A computer chip manufacturer knows that 72% of the chips produced are defective.

Mathematics

1 answer:

adoni [48]2 years ago

5 0

The probability that exactly 800 chips are acceptable is less than 0.000001

<h3>How to determine the probability?</h3>

The given parameters are:

Sample, n = 3000
Percentage acceptable, p = 72%
Acceptable chips, x = 800

The binomial probability is represented as:

$P(x) = ^nC_x * p^x * (1- p)^{n - x}$

So, we have:

$P(300) = ^{3000}C_{800} * (72\%)^{800} * (1- 72\%)^{3000 - 800}$

The data values are large.

So, we use a statistical calculator to evaluate the expression

Using the calculator, we have:

P(300) < 0.000001

Hence, the probability that exactly 800 chips are acceptable is very small i.e. less than 0.000001

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The sum of three certain consecutive numbers is 240. Find the 3 numbers.

BartSMP [9]

Answer:79 , 80 , 81

Step-by-step explanation:What three consecutive integers have a sum of 240? What three consecutive integers have a sum of 240? Which means that the first number is 79, the second number is 79 + 1 and the third number is 79 + 2. Therefore, three consecutive integers that add up to 240 are 79, 80, and 81.

5 0

3 years ago

Which equation is parallel to the graph of y = 2x-5 and goes through the point (3,9)?

lawyer [7]

Answer:

y = 2x + 3

Step-by-step explanation:

the slope is 2 so the line parallel will have a slope of 2

y-9 = 2(x-3)

y-9= 2x - 6

y = 2x +3

6 0

2 years ago

Can Someone Answer My Final Answers :) I’d appreciate it so much :)

DaniilM [7]

1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$
where
$(x_{1},y_{1})$ are the coordinates of the first point
$(x_{2},y_{2})$ are the coordinates of the second point
Length of WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
$d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}$
$d_{WZ}= \sqrt{(3)^2+(2)^2}$
$d_{WZ}= \sqrt{9+4}$
$d_{WZ}= \sqrt{13}$

We know that all the sides of a rhombus have the same length, so
$d_{YZ}= \sqrt{13}$
$d_{XY}= \sqrt{13}$
$d_{XW}= \sqrt{13}$

Now, we just need to add the four sides to get the perimeter of our rhombus:
$perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}$
$perimeter=4 \sqrt{13}$
We can conclude that the perimeter of our rhombus is $4 \sqrt{13}$ square units.

2. To solve this, we are going to use the arc length formula: $s=r \alpha$
where
$s$ is the length of the arc.
$r$ is the radius of the circle.
$\alpha$ is the central angle in radians

We know form our problem that the length of arc PQ is $\frac{8}{3} \pi$ inches, so $s=\frac{8}{3} \pi$ , and we can infer from our picture that $r=15$ . Lest replace the values in our formula to find the central angle POQ:
$s=r \alpha$
$\frac{8}{3} \pi=15 \alpha$
$\alpha = \frac{\frac{8}{3} \pi}{15}$
$\alpha = \frac{8}{45} \pi$

Since $\alpha =POQ$ , We can conclude that the measure of the central angle POQ is $\frac{8}{45} \pi$

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section.
We can conclude that the draw of our cross section is: