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4 years ago

Please help. I'm trying to help my son with this and I'm so confused.

Mathematics

1 answer:

andre [41]4 years ago

7 0

Answer: C and D

Step-by-step explanation:

Equations C and D both have a slope of 0, that way they are parallel to the x-axis and perpendicular to the y-axis as both equations are interms of y.

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Pls help me figure out the slope

cluponka [151]

Answer:

$m=\frac{-4}{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (-3, 1)

Point (2, -3)

Step 2: Find slope m

Substitute: $m=\frac{-3-1}{2+3}$
Subtract/Add: $m=\frac{-4}{5}$

7 0

3 years ago

If a 24 pack of cans is 2 for $9 what is the ratio of the number of cans to price

Salsk061 [2.6K]

2:9 should be the answer

5 0

3 years ago

Read 2 more answers

Twin brothers,billy and Bobby, can mow their grandparents lawn together in 72 minutes. Billy could mow the lawn by himself in 15

Alla [95]

Answer:

Billy used 28 mins 30 sec to mow the lawn and Bobby used 43 mins 30 sec to now the lawn both within 72 mins

Step-by-step explanation:

let x represent Billy

let x+15 represent Bobby

x + x + 15 = 72

2x = 72 - 15

2x = 57

2x/2 = 57/2

x = 28.5 minutes = 28 minutes 30 seconds

Bobby = x + 15

= 28.5 + 15

= 43.5 minutes= 43 minutes 30 seconds

6 0

3 years ago

Ray CE is the angle bisector of ACD. Which statement about the figure must be true?

Viefleur [7K]

we know that

"Bisect" means to divide into two equal parts

If the ray CE is the angle bisector of ADC

then

$Angle(ACD)=Angle(ACE)+Angle(ECD)$

$Angle(ACE)=Angle(ECD)$

$Angle(ACD)=2Angle(ACE)$

$Angle(ACE)=\frac{1}{2} Angle(ACD)$

therefore

the answer is the option

$Angle(ACE)=\frac{1}{2} Angle(ACD)$

$Angle(ACE)=Angle(ECD)$

7 0

3 years ago

Read 2 more answers

Solve the system using elimination. 2x + 3y = 17 x + 5y = 19

ale4655 [162]

$\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.$

5 0

3 years ago