All categories

1 year ago

In a unit circle, ø = 360°. What is the terminal point?

1 answer:

3 0

The terminal point is (0, 1) if the radius of circle is 1 and the value of an angle ø is 360 degree option (C) is correct.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

We have a unit circle with an angle ø = 360 degree.

The terminal point will be:

x = rcosø

y = rsinø

r = 1

ø = 360 degree

x = cos360 = 1

y = sin360 = 0

The terminal point (0, 1)

Thus, the terminal point is (0, 1) if the radius of circle is 1 and the value of an angle ø is 360 degree option (C) is correct.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

You might be interested in

Which of the following statements is always true?

yKpoI14uk [10]

Workers being paid on commission get paid based solely on their performance.
They get paid based on their performance and not their hours.

3 0

2 years ago

Read 2 more answers

Amanda simplifies the following expression and shows her work below. What mistake did Amanda make that resulted in an incorrect

den301095 [7]

Answer:

A, She added before multiplying.

Step-by-step explanation:

First, start off by using GEMDAS.

Grouping

Exponents

Multiply

Divide

Add

Subtract

You work from left to right - so you obviously divide first, which Amanda did successfully. Then, you multiply, which is exactly where Amanda went wrong. She was supposed to multiply before adding the 3 with 4.

Not sure if this made sense,

8 0

1 year ago

If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$

from (1)(2) => proven

5 0

2 years ago

an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

Hitman42 [59]

We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total.

5 0

2 years ago

Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.

zlopas [31]

Answer:

x = 1

Explanation:

$\sf \rightarrow log(3x) + log(x + 4) = log(15)$