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Svetach [21]
1 year ago
13

In a unit circle, ø = 360°. What is the terminal point?

Mathematics
1 answer:
Tom [10]1 year ago
3 0

The terminal point is (0, 1) if the radius of circle is 1 and the value of an angle ø is 360 degree option (C) is correct.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

We have a unit circle with an angle ø = 360 degree.

The terminal point will be:

x = rcosø

y = rsinø

r = 1

ø = 360 degree

x = cos360 = 1

y = sin360 = 0

The terminal point (0, 1)

Thus, the terminal point is (0, 1) if the radius of circle is 1 and the value of an angle ø is 360 degree option (C) is correct.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

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PLS ANSWER
avanturin [10]

The set of points that represents a function is given by:

A {(2, 1), (7, 9), (3, 12), (4, 10)}.

<h3>When does a relation represents a function?</h3>

A set, or a relation, represents a function when <u>each value of x is mapped to only one value of y</u>.

In this problem, we have that option A represents a function, as:

  • In option B, x = 2 and x = -2 are mapped to two values.
  • In option C, x = 4 is mapped to four values.
  • In option D, both x = 1 and x = 2 are mapped to two values.

Hence the set of points that represents a function is given by:

A {(2, 1), (7, 9), (3, 12), (4, 10)}.

More can be learned about relations and functions at brainly.com/question/12463448

#SPJ1

8 0
2 years ago
What is 10 x 6 please answer assap
rosijanka [135]
60 that's the answer.
7 0
3 years ago
Find the 12th term of an AP of the form 7, 12, 17, 22
ikadub [295]
Answer: 62

Step-by-Step Explanation:

First Term (a) = 7
Common Difference (d) = 12 - 7 = 5
Term to Find (n) = 12th

Therefore, finding the 12th Term :-
=> a+(n-1)d
= 7 + (12 - 1)5
= 7 + (11)5
= 7 + 55
=> 62

Hence, 12th Term of this AP is 62
4 0
2 years ago
Read 2 more answers
What is the domain of the relation y = arccscx?
Stella [2.4K]

Answer:

y=arc\csc x

Step-by-step explanation:

The given function is y=arc\csc x.

The domain refers to all values of x for which this function is defined.

Recall that: the domain of y=arc \sin (x) is -1\le x\le1

And we know y=arc\csc x is the reciprocal of y=arc \sin (x).

Therefore the complement of the domain of y=arc \sin (x) which is (-\infty,-1]\cup [1,+\infty) is the domain of y=arc\csc x

5 0
3 years ago
Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
3 years ago
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