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2 years ago

65yards and 2feet equall hiw many feet

2 answers:

5 0

We know that 1 yard equals 3 feet, therefore, we have:
65(3) + 2
= 195 + 2
= 197
therefore, 65 yards and 2 feet equals 197 feet

STatiana [176]2 years ago

3 0

197 feet. You will get this answer by multiplying 65 yards x 3. This is because 3 feet is in 1 yard. You will then get 195 feet. Lastly, you would add the last 2 feet to get the answer.

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Find one solution for the equation. Assume that all angles involved are acute angles.

Nikitich [7]

9514 1404 393

Answer:

B = 13

Step-by-step explanation:

The tangent and cotangent are equal when the angles are complementary.

(3B +35) +(2B -10) = 90

5B = 65

B = 13

___

<em>Check</em>

For B=13, the angles are 3B+35 = 39+35 = 74, and 2B-10 = 26-10 = 16. Both are acute angles.

5 0

3 years ago

Draw the graph y = 4 x - 1 on the grid

kkurt [141]

Answer:

From the graph, it is also clear that at $y=1$ , the value

of $x=\frac{1}{2}$ .

Step-by-step explanation:

Given the equation

$y = 4 x - 1$

The graph is attached below.

Putting $y=1$ in the equation to find the value of x

$y = 4 x - 1$

$1 = 4x-1$

$2 = 4x$

$x=\frac{2}{4}$

$x=\frac{1}{2}$

From the graph, it is also clear that at $y=1$ , the value

of $x=\frac{1}{2}$ .

8 0

3 years ago

Heidi and Andrew designed two raised flowerbeds for their garden. Heidi's flowerbed was 5 feet long by 3 feet wide, and Andrew's

d1i1m1o1n [39]

Answer:

$V=90\ ft^3$

Step-by-step explanation:

-Given the two heights are similar:

#Heidi's flowered bed dimensions and volume is calculated as:

$v=lwh$

$=5\times 3\times 2\\\\=30\ ft^3$

#The width of Andrew's is twice Heidi's. The width and volume is thus calculated as:

$w_a=2\times 3=6 \ ft\\\\V_a=lwh\\\\=5\times 6 \times 2\\\\=60\ ft^3$

#Total soil volume of the soil used is determined by summing the two different flowerbed volumes:

$V=V_h+V_a\\\\=30+60\\\\=90 \ ft^3$

7 0

3 years ago

Completely factor this polynomial:<br> 16x2-25y2

Furkat [3]

$16x^2-25y^2=(4x)^2-(5y)^2=(4x-5y)(4x+5y)$

3 0

2 years ago

We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent

Nikitich [7]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 : Result on 1st die.

- Random Variable X_2: Result on 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

( X = -2 ): { X_2 = 1 , X_1 = 3 }

P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }

P ( X = -1 ):3*P ( X_2 = 1 )*P ( X_1 = 1 )

: 3*( 1 / 3 ) * ( 1 / 3 )

: ( 3 / 9 ) = ( 1 / 3 )

( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

P ( X = 1 ): 2* P ( X_2 = 2 ) * P ( X_1 = 1 )

: 2* ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 2 ): { X_2 = 1 , X_1 = 3 }

P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

- The distribution Y = X_2,

P(Y=0) = 0

P(Y=1) = 1/3

P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

8 0

3 years ago