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makvit [3.9K]
3 years ago
14

1. 0.68 = 0.6 + _____ =_____ x 0.1 +8 x ____. 2. 0.031 = _____ x 1/100 + _____ × 1/1000​

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Step-by-step explanation:

0.68=0.6+.08=6x0.1+8x.01

0.031=3x1/100+1×1/1000

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Finger [1]

Answer:

I don't see an equation to solve

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3 years ago
1. How do I find the slope of (2,4) (4,7)
Goshia [24]

Answer: 3/2

Step-by-step explanation:

Rise over run!!!

Subtract y values, divide that by the subtracted x values.

7-4/4-2= 3/2

4 0
3 years ago
Question 4 A family has two cars. The first car has a fuel efficiency of miles per gallon of gas and the second has a fuel effic
lesya [120]

Complete question is;

A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 40 miles per gallon of gas. During one particular week, the two cars went a combined total of 1850 miles, for a total gas consumption of 50 gallons. How many gallons were consumed by each of the two cars that week?

Answer:

Car 1 consumed 30 gallons of gas.

Car 2 consumed 20 gallons of gas.

Step-by-step explanation:

Let x be number gallons consumed by car 1

Let y be number of gallons consumed by car 2

We are told that total gas consumption of 50 gallons. Thus;

x + y = 50 - - - - - eq(1)

We are told that the first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 40 miles per gallon of gas and they went a combined total of 1850 miles. Thus;

35x + 40y = 1850 - - - - eq2

Let's make y the subject in eq(1),

y = 50 - x - - - - eq(3)

Putting 50 - x for y in eq 2 gives;

35x + 40(50-x) = 1850

35x + 2000 - 40x = 1850

-5x + 2000 = 1850

-5x = -150

x = 150/5

x = 30 gallons

Substitute 30 for x into eq 3,we have;

y = 50 - 30

y = 20 gallons

Thus;

Car 1 consumed 30 gallons of gas.

Car 2 consumed 20 gallons of gas.

3 0
4 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
lucky charms cereal uses 1 1/3 of weat pieces for every 1/5 cups of marshmellow pieces how many cups of weat pieces are in a box
kobusy [5.1K]

Answer:

Step-by-step explanation:

you do 11\3 divided by 1\5

4 0
3 years ago
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