Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
Answer:
WHY IS THIS IN CAPS
Step-by-step explanation:
AAAAAAAAAAAAAAARRRRRRRGGGGHHHHH
Y axis is counting by 2's
it started at 2 and went up to 6
Y = 4
X axis is counting by 2'2
starts at one goes to 3
X = 2
Slope is 4/2 because rise over run
4/2 = 2
Slope is simplified to 2.
Answer:
Step-by-step explanation:
hmmmmmmmmmm
Answer: https://mathsolver.microsoft.com/en/solve-problem/2x+4y-8=0
Step-by-step explanation: you should find your answer there
