Answer: E(X) = 30; Var[X] = 180
Step-by-step explanation: This is a <u>Bernoulli</u> <u>Experiment</u>, i.e., the experiment is repeated a fixed number of times, the trials are independents, the only two outcomes are "success" or "failure" and the probability of success remains the same, So, to calculate <em><u>Expected</u></em> <em><u>Value</u></em>, which is the mean, in these conditions:

r is number of times it is repeated
p is probability it happens
Solving:

E(X) = 30
<u>Variance</u> is given by:
![Var[X]=\frac{r(1-p)}{p^{2}}](https://tex.z-dn.net/?f=Var%5BX%5D%3D%5Cfrac%7Br%281-p%29%7D%7Bp%5E%7B2%7D%7D)
![Var[X]=\frac{5(1-1/6)}{(1/6)^{2}}](https://tex.z-dn.net/?f=Var%5BX%5D%3D%5Cfrac%7B5%281-1%2F6%29%7D%7B%281%2F6%29%5E%7B2%7D%7D)
![Var[X]=5.\frac{5}{6}.6^{2}](https://tex.z-dn.net/?f=Var%5BX%5D%3D5.%5Cfrac%7B5%7D%7B6%7D.6%5E%7B2%7D)
Var[X] = 180
Expected Value and Variance of the number of times one must throw a die until 1 happens 5 times are 30 and 180, respectively.
Answer:
48 and 32 6 hours clearing tables and 2 hours tutoring
Step-by-step explanation:
we can rewrite this as a fraction. we will use 1/10s because 80 can be divided by 8 which is in the problem. we then have to find out what two numbers add up to 8 but one is 3 times the other. 6 and 2 fit into this problem so we plug it into the equation and we write it as this 6x+4x=80 where x is 8. we get 48 and 32.
Answer:
16
Step-by-step explanation:
The mean of a group of values is calculated as
mean = 
Given 5 numbers with a mean of 12, then
= 12 ( multiply both sides by 5 )
sum = 60
let the number removed be x , then
= 11 ( multiply both sides by 4 )
60 - x = 44 ( subtract 60 from both sides )
- x = - 16 ( multiply both sides by - 1 )
x = 16
The number removed was 16
Answer:
0.105 = 10.5% probability that an accident results in a death.
Step-by-step explanation:
What is the probability that an accident results in a death?
5% of 60%(sunny)
25% of 20%(foggy)
12.5% of 20%(rainy)
So

0.105 = 10.5% probability that an accident results in a death.