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2 years ago

Name any outliers in the data 277,448,279,334,132,599,237,251,183, and 191

Mathematics

1 answer:

enyata [817]2 years ago

5 0

448, 599, and 183....

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The sum of the first four terms of an arithmetic sequence is $10$. If the fifth term is $5$, what is the sixth term?

Nookie1986 [14]

The sixth term of an arithmetic sequence is 6

<h3>How to find arithmetic sequence?</h3>

The sum of the first four terms of an arithmetic sequence is 10.

The fifth term is 5.

Therefore,

sum of term = n / 2(2a + (n - 1)d)

where

a = first term
d = common difference
n = number of terms

Therefore,

n = 4

10 = 4 / 2 (2a + 3d)

10 = 2(2a + 3d)

10 = 4a + 6d

4a + 6d = 10

a + 4d = 5

4a + 6d = 10

4a + 16d = 20

10d = 10

d = 1

a + 4(1) = 5

a = 1

Therefore,

6th term = a + 5d

6th term = 1 + 5(1)

6th term = 6

learn more on sequence here: brainly.com/question/24128922

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7 0

9 months ago

Find the area of this circle please…Use 3 for pi

ZanzabumX [31]

Given:

The radius of circle is 11 inch

The value for pi is 3

The objective is to find the area of the circle.

The area of the circle is given by the formula:

$A=\pi\times r^2^{}$

Substituting ,r = 11

$\pi=3$

We get:

$\begin{gathered} A=\pi\times r^2 \\ =3\times(11)^2 \\ =3\times121 \\ =363 \end{gathered}$

Hence, the area of the circle is 363 square inches

5 0

10 months ago

At the 2007 Math Olympics, Team Canada won 17 out of a possible 100 medals. Which one of the following is closest to the fractio

irinina [24]

Answer:1/8

Step-by-step explanation:

3 0

2 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 500(1.075)120x = 100.000

Volgvan

Answer:

The solution is:

$x = 0.61$

Step-by-step explanation:

The first step to solve this equation is placing everything with the exponential to one side of the equality, and everything without the exponential to the other side. So

$500(1.075)^{120x} = 100000$

$(1.075)^{120x} = \frac{100000}{500}$

$(1.075)^{120x} = 200$

To find x, we have to apply log to both sides of the equality.

We also have that:

$\log{a^{x}} = x\log{a}$

$\log{(1.075)^{120x}} = \log{200}$

$120x\log{1.075} = 2.30$

$120x*0.03 = 2.30$

$3.77x = 2.30$

$x = \frac{2.30}{3.77}$

$x = 0.61$

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2 years ago

Guys I need help, this is so important for my grade

Dmitrij [34]

Answer:

For Part C) use numbers 1 2 3 4.

Step-by-step explanation:

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2 years ago