Question

A landscaper has 10 2/5 cubic yards of peat moss in a truck. If he unloads 2 2/3 cubic yards at the first site and 2 1/4 cubic yards at the second site, how many cubic yards of peat moss remain for the third site?

Answer 1

Step-by-step explanation:

The problem bothers on fractions, here we are being presented with mixed fractions.

what we are going to do bascially is to subtract the sum of all the uloaded

peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site

therefore

$10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})$

we then have to convert the mixed fraction to further simplify the problem we have

$\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})$

we then solve the fraction to the right of the negative symbol first

$=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}$

We can now convert to mixed fraction

$=\frac{329}{60}\\\\ =5\frac{12}{25}$

For the third site the remainder is 5 12/25