Step-by-step explanation:
Data Set A: 14, 21, 24, 28, 28, 35
Data Set B: 18, 19, 21, 25, 29,32
Median:
Data Set A = 26
24 + 28 = 52
52/2 = 26
Data Set B = 23
21 + 25 = 46
46/2 = 23
Mean:
Data Set A = 25
14 + 21 + 24 + 28 + 28 + 35 = 150
150/6 = 25
Data Set B = 24
18 + 19 + 21 + 25 + 29 + 32 = 144
144/6 = 24
Answer:
69.3 meters squared
Step-by-step explanation:
1) Think of the shape as being divided into two sections (a rectangle and a triangle)
2) multiply 5.2 times 7 to find the area of the rectangle (36.4)
3) subtract 5.2 from 14.6 to find the base of the triangle (9.4)
4) multiply 9.4 by the height of the triangle 7 (65.8)
5) divide 65.8 by two because a triangle is half of the needed rectangle
6) this leaves 32.9
7) add 32.9 and 36.4 to get your final answer of 69.3 meters squared
hope this helps :)
ANSWER(S):
5 laps
EXPLANATION(S):
distance formula: d= rt; d= d, r= 1/6, t= 30
d= (1/6)(30)
d= 5
5 laps
Answer:
The solution is:
z (max ) = 446.25 $
x₁ = 55 x₂ = 0 x₃ = 5 x₄ = 70
Step-by-step explanation:
From problem statement:
Nacholupa Quesatilla Enchinacho Burritaco
x₁ x₂ x₃ x₄
Cheese 2 4 2 4
meat 0 2 2 2
beans 4 0 2 0
Tortillas 3 1 3 1
Price $ 2.75 2 3 4
From table :
z = 2.75*x₁ + 2*x₂ + 3*x₃ + 4*x₄ to maximize
Subject to:
Availability of cheese: 400 ou
2*x₁ + 4*x₂ + 2*x₃ + 4*x₄ ≤ 400
Availability of meat : 150 ou
2*x₂ + 2*x₃ + 2*x₄ ≤ 150
Availability of beans : 400 ou
4*x₁ + 2*x₃ ≤ 400
Availability of tortillas : 250
3*x₁ + x₂ + 3*x₃ + x₄ ≤ 250
General constraints:
x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 x₄ ≥ 0
All integers
With the use of AtomZmath ( integer solving on-line software )
The solution is:
z (max ) = 446.25 $
x₁ = 55 x₂ = 0 x₃ = 5 x₄ = 70
Answer:
.23 x 10-6 g.
Step-by-step explanation: