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MaRussiya [10]
2 years ago
7

At the stadium, there are eight lines for arriving customers, each staffed by a single worker. The arrival rate for customers is

190 per minute and each customer takes (on average) 2 seconds for a worker to process. The coefficient of variation for arrival time is 1.2 and the coefficient of variation for service time is 1.5. (1) How much time (in seconds) will an average customer spend in queue
Mathematics
1 answer:
Evgen [1.6K]2 years ago
7 0

Answer:

3.287 Customers

Step-by-step explanation:

Interarrival time (a) = 60 seconds per minute / 190 customers per minute = 0.316 seconds.

Utilization = p / (a × m) = 2 / (0.316 × 8) = 0.792.

Number in queue = Tq / a = 1.038 / 0.316 = 3.287 customers.

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Carlo and his two brothers helped to decorate the house for the party. Each of them blows 12 balloons. But 5 balloons pop. How m
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Answer:

31

Step-by-step explanation:

thye blow up 36 balloons in total but 5 pop 36-5=31

4 0
2 years ago
 They spent $18 on tickets to the carnival and $36 on food.  They spent the rest of the money on g They spent $18 on tickets
Reptile [31]

Answer:

93 = g + 36 + 18

Step-by-step explanation:

8 0
3 years ago
What is 352.694<br> In expanded notation
Diano4ka-milaya [45]
   
\displaystyle \bf\\&#10;352.694 = 3\times100+5\times10+2\times1+ 6\times\frac{1}{10}+9\times\frac{1}{100}+4\times\frac{1}{1000}


6 0
4 years ago
The coordinates of three of the vertices of parallelogram ABCD are A(1, 0), B(2, 3), C(3, 2). What are coordinates of the fourth
nalin [4]

Answer:

 A) The coordinates of the fourth vertex are:

1) x-coordinate:

x=2

2) y-coordinate:

y=-1

B) The point of intersection of the diagonals is:  (2,1)

Step-by-step explanation:

We need to remember that the diagonals of a parallelogram intersect each other at a half-way point and the midpoint of each diagonal is the same.

The midpoint formula is:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since:

M_{AC}=M_{BD}

We can find the coordinates of the fourth vertex D(x,y) through these procedure:

1) x-coordinate:

\frac{1+3}{2}=\frac{2+x}{2}\\\\2(2)=x\\\\4-2=x\\\\x=2

2) y-coordinate:

\frac{0+2}{2}=\frac{3+y}{2}\\\\1(2)-3=y\\\\y=-1

Therefore,  fourth vertex is D(2,-1)

Since the point of intersection of the diagonals is the midpoint of a diagonal (Remember that  M_{AC}=M_{BD}), this is:

M_{AC}=M_{BD}=(\frac{1+3}{2},\frac{0+2}{2})\\\\M_{AC}=M_{BD}=(2,1)

Therefore, the point of intersection of the diagonals is (2,1)

7 0
3 years ago
Solve (x + 2 &lt; 5) ∩ (x - 7 &gt; -6).
mihalych1998 [28]

Answer:

<h2>1. {x | 1 < x < 3}</h2>

Step-by-step explanation:

x + 2 < 5           <em>subtract 2 from both sides</em>

x + 2 - 2 < 5 - 2

x < 3

x - 7 > -6        <em>add 7 to both sides</em>

x > 1

From x < 3 and x > 1 we have 1 < x < 3

7 0
3 years ago
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