The expected value is $8,000.
Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
Answer:
27x +42+ 3x²
Step-by-step explanation:
so im learning this rn in class and what you do is FOIL
So its stands for
First
Outside
Inside
Last
(3x+6)(x+7)
(3x+6)(x+7) -- 3x² (if you have x times x it is x to the second power)
(3x+6)(x+7) -- 21x
(3x+6)(x+7) -- 6x
(3x+6)(x+7) -- 42
Now add 21x and 6x
27x +42+ 3x²
you must have added the 21 and 6 incorrectly.
Answer:
it's not 100 or 102, just took the test and got them both wrong.
Step-by-step explanation:
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