Answer:
the normal distribution is a symmetric distribution with no skew. ... A left-skewed distribution has a long left tail. Left-skewed distributions are also called negatively-skewed distributions. That's because there is a long tail in the negative direction on the number line.
Answer:
The next step is to Divide 35 by 5 then solve for x
Step-by-step explanation:
Answer: total profit = $418
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Work Shown:
June
Income = (4 lawns)*($27 per lawn) = $108
Expenses = ($32 for gas)+($12 for trim line) = $44
Profit = income - expenses = 108-44 = $64
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July
Income = (12 lawns)*($20 per lawn) = $240
Expenses = ($89 for gas)+($29 for blade sharpening) = $118
Profit = income - expenses = 240 - 89 = $151
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August
Income = (16 lawns)*($20 per lawn) = $320
Expenses = ($101 for gas)+($16 for oil) = $117
Profit = income - expenses = 320-117 = $203
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Total profit = (june profit)+(july profit)+(august profit)
Total profit = (64) + (151) + (203)
Total profit = $418
If the final result was negative, then we would call this a loss. However, we have a positive value, so we go with a profit.
Answer:
see attached
Step-by-step explanation:
At 1100 ft per second for 18 seconds, the sound travels 19,800 ft, or 3.75 miles farther to my friend's house. The set of points that lie 3.75 miles farther from my friend's house than from my house form a hyperbolic curve. This is illustrated by the blue line in the attached graph. (My house is the red dot on the left; my friend's house is the red dot on the right.)
The lightning occurred somewhere on the blue curve.
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If the lightning occurred on the line between our houses, it was 1/8 mile from my house and 3 7/8 mile from my friend's house. (That's close!)
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The formula for the curve in the graph is the distance formula applied to the set of points (x, y). It equates the difference of distance from the two houses to 3.75 miles. If one were to write the equation of the hyperbola in standard form, the equation would look a little different and a restriction would need to be applied so the formula would describe only one branch of the hyperbola.