<span>Let the 2 consecutive odd integers be represented by:
"x" and "(x+2)
_________________
The product of these two consecutive odd integers is:
________________
</span>→ <span>x*(x + 2); or, write as: x(x + 2)
__________________
The sum </span>of these two consecutive odd integers is:
<span>________________________________
</span>→ <span>x + (x + 2) = (2x + 2)
_______________________________
The product of 2 conductive integers, "</span>x(x + 2)" , is 1 less than
4 times their sum, "(2x + 2)".
<span>______________________________
</span>→ Write as: 4*(2x + 2) − 1 = x(x + 2)
<span>________________________________
Note the distributive property of multiplication:
_______________________________
</span>→ <span>a*(b + c) = ab + ac ;
________________________________
We have:
___________
</span>→ 4*(2x + 2) − 1 = x(x + 2)
<span>_____________________________
</span> → 4*(2x + 2) = (4*2x) + (4*2) = 8x + 8
<span>____________________________________
On the "right side of the equation; we have:
______________________________________
</span>→ x(x + 2) = (x*x) + (x*2) = x² + 2x
<span>_____________________________________
We can rewrite the equation:
__________________________
</span>→ 4*(2x + 2) − 1 = x(x + 2) ;
<span>___________________________
by substituting our obtained "expanded values" for:
"[</span>4*(2x + 2)]" ; and for: "[x(x + 2)]" ;
<span>______________________________________
</span>→ 4*(2x + 2) − 1 = x(x + 2) =
____________________________
→ 8x + 8 − 1 = x² + 2x ;
__________________________________
→ Simplify the "+8 − 1" on the "left-hand side" of the equation to "7"; and subtract "2x" from EACH SIDE of the equation:
<span>____________________________________
</span>→ 8x + 7 − 2x = x² + 2x − 2x ; to get:
<span>____________________________
</span> → 6x + 7 = x² ;
________________________________
→To solve for "x"; Subtract "6x" and subtract "7"; from EACH SIDE of the equation; to get an equation in "quadratic format" ; that is:
<span>_____________________________________________
ax
let x and x+2 be the consecutive odd integers.
Their product is x(x+2)
Their sum is x + x+2 or 2x+2
x(x+2)=4(2x+2)-1
Domain is odd integers</span>
Answer:
dang nice
Step-by-step explanation:
He has thrown 425 free throws if he missed 17
<h3>How to determine the total number of free throws?</h3>
The given parameters are:
Proportion of free throw missed, p = 4%
Number of free throw missed, n = 17
Let the total number of throws be N.
So we have
n = p * N
Substitute the known values in the above equation
17 = 4% * N
Divide both sides by 4%
N = 425
Hence, he has thrown 425 free throws if he missed 17
Read more about proportion at:
brainly.com/question/18437927
#SPJ1
Answer:
theta = 4.5642792103077898247
Step-by-step explanation:
0 <= theta < 2Pi sin(theta) = 1/2
so
2Pi sin(theta) = 1/2
Pi sin(theta) = 1/4
sin(theta) = 1/(4Pi)
sin(theta) = .0795774715459
theta = arcsin(.0795774715459) = 4.5642792103077898247
