Answer:
x ≈ 25.4 Km
Step-by-step explanation:
Using the tangent ratio in the right triangle on the right
tan54° =
=
( multiply both sides by 17 )
17 × tan54° = opp , thus
opp ≈ 23.4
-------------------------------------------
Using the cosine ratio in the right triangle on the left
cos23° =
=
( multiply both sides by x )
x × cos23° = 23.4 ( divide both sides by cos23° )
x =
≈ 25. 4 Km ( to the nearest tenth )
Multiply it out
x^2 + 4x -8x -32
Combine like terms
x^2 -4x - 32
Answer:
Greater than/equal to 9
Step-by-step explanation:
-⅓m《-3
3《⅓m
3×3《m
9《m
m》9
Answer:
b is 16 d is 13
Step-by-step explanation:
ok is a baby girl that can I be happy
Answer:

Step-by-step explanation:
The <u>width</u> of a square is its <u>side length</u>.
The <u>width</u> of a circle is its <u>diameter</u>.
Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.
<u>Formulas</u>



If the diameter is equal to the side length of the square, then:

Therefore:

So the ratio of the area of the circle to the original square is:

Given:
- side length (s) = 6 in
- radius (r) = 6 ÷ 2 = 3 in


Ratio of circle to square:
